Answer:
The chemical potential of 2-propanol in solution relative to that of pure 2-propanol is lower by 2.63x10⁻³.
Explanation:
The chemical potential of 2-propanol in solution relative to that of pure 2-propanol can be calculated using the following equation:
<u>Where:</u>
<em>μ (l): is the chemical potential of 2-propanol in solution </em>
<em>μ° (l): is the chemical potential of pure 2-propanol </em>
<em>R: is the gas constant = 8.314 J K⁻¹ mol⁻¹ </em>
<em>T: is the temperature = 82.3 °C = 355.3 K </em>
<em>x: is the mole fraction of 2-propanol = 0.41 </em>
Therefore, the chemical potential of 2-propanol in solution relative to that of pure 2-propanol is lower by 2.63x10⁻³.
I hope it helps you!
Answer:
A conductor is a material that permits electrons to effortlessly go through it. Copper is a good conductor. Note that the valence shell has just a single electron.
While;
Materials that don't conduct are named insulators.(i.e. glass, porcelain, plastic, elastic. The covering on electrical wire is an insulator.)
Insulators don't conduct since they have a full or almost full valence shell and along these lines their electrons are firmly bound.
Explanation:
According to Bohr Rutherford model of Atom, An Atom contains three essential particles; Protons and neutrons that make up the nucleus and the electrons that circle or orbit the nucleus. The electrons circle the nucleus.
Molar mass HCl = 1.01 + 35.45 => 36.46 g/mol
number of moles:
mass HCl / molar mass
9.63 / 36.46 => 0.2641 moles of HCl
Therefore:
M = moles / Volume ( in liters )
M = 0.2641 / 1.5
M = 0.1760 mol/L⁻¹
Answer:
Lots of bad things would happen
Explanation:
People would lose their jobs
People would fall out of contact (no phones)
It would be pretty dark (no streetlights)
You would have to learn everything by book or asking someone
ect.
Answer:
0.354 molal
Explanation:
The molarity (M) or the concentration of a solution is defined as the number of moles of a compound in the solution per liter of solution (mol/L), whereas molality, is defined as the number of moles of a compound in the solution per kg of the compound (mol/kg).
Given that the density of the solution is 1.202 g/mL, which is equivalent to 1.202 kg/L. Since the prefix mili- denotes a factor of one thousandth ( 
) and kilo- denotes a factor of one thousand ( 
),
.
To calculate the corresponding molality of the solution, the formula
is used.
Therefore,
