There are four sublevels s, p, d ,f 2 in the s
6,50g of ZnSO4 is 0,04 moles
Mass
of ZnSO4 :
m=6,50g
<span>Molar
mass of ZnSO<span>4 : </span></span>
M=M(Zn)+M(S)+4*M(O)
M=65,38
g/mol+32,06 g/mol+4*15,99 g/mol
M=161,40 g/mol
Molarity of ZnSO4 :
n=m/M
n=6,50g/161,40g/mol
n=0,04 mol
Answer:
Heterogeneous- C, Homogeneous-D, Emulsion-B, Colloid-A
Explanation:
First lets do Rb..we have 1 one the left and 3 on the right. so 3RbOH will balance that
PO4 is equal on both side
since we put 3 for RbOH now we have 3 O on the left
so we put 3 for H2O
now we have 6 H on each side so everything is balanced