Answer:
parallel connection:Advandages: 1. Every unit that is connected in a parallel circuit gets equal amount of voltage.2. It becomes easy to connect or disconnect a new element without affecting the working of other elements.3. If any fault happened to the circuit, then also the current is able to pass through the circuit through different paths.Disadvantages: 1. It requires the use of lot of wires.2. We cannot increase or multiply the voltage in a parallel circuit.3. Parallel connection fails at the time when it is required to pass exactly same amount of current through the units.series connection:Advantages: 1. Series circuits do not overheat easily. This makes them very useful in the case of something that might be around a potentially flammable source, like dry plants or cloth.2. Series circuits are easy to learn and to make. Their simple design is easy to understand, and this means that it’s simple to conduct repairs .3. we can add more power devices, they have a higher output in terms of voltage .4. The current that flows in a series circuit has to flow through every component in the circuit. Therefore, all of the components in a series connection carry the same current.Disadvantages: 1.If one point breaks in the series circuit,the total circuit will break.2. As the number of components in a circuit increases ,greater will be the circuit resistance.
Answer:
ee that the lens with the shortest focal length has a smaller object
Explanation:
For this exercise we use the constructor equation or Gaussian equation
where f is the focal length, p and q are the distance to the object and the image respectively.
Magnification a lens system is
m =
= -
h ’= -\frac{h q}{p}
In the exercise give the value of the height of the object h = 0.50cm and the position of the object p =∞
Let's calculate the distance to the image for each lens
f = 6.0 cm

as they indicate that the light fills the entire lens, this indicates that the object is at infinity, remember that the light of the laser rays is almost parallel, therefore p = inf
q = f = 6.0 cm
for the lens of f = 12.0 cm q = 12.0 cn
to find the size of the image we use
h ’= h q / p
where p has a high value and is the same for all systems
h ’= h / p q
Thus
f = 6 cm h ’= fo 6 cm
f = 12 cm h ’= fo 12 cm
therefore we see that the lens with the shortest focal length has a smaller object
DRAG is the sum of all the aerodynamic or hydronamic forces in the direction of the external fluid flow.
Answer:
The angular speed of the Crab nebula pulsar is 190.3 rad/s.
Explanation:
Given that,
Time T= 33 ms = 0.033 s
The angular speed is equal to the 2π divided by time period.
We need to calculate the angular speed of the Crab nebula pulsar
Using formula of angular speed

Where, T = time
= angular speed
Put the value into the formula


Hence, The angular speed of the Crab nebula pulsar is 190.3 rad/s.
Answer:
E = 
Explanation:
For this exercise let's use Gauss's law. The Gaussian surface that follows the symmetry of the charges is a sphere
Ф = ∫ E. dA =
the bold are vectors, the radii of the sphere and the electric field are parallel therefore the scalar product reduces to the algebraic product
Ф = ∫ E dA = \frac{x_{int} }{\epsilon_o}
E ∫ dA = \frac{x_{int} }{\epsilon_o}
E A = \frac{x_{int} }{\epsilon_o}
the area of a sphere is
A = 4π r²
the charge inside the sphere is q = + q
we substitute
E 4π r² = \frac{x }{\epsilon_o}
E = 