Answer:
The correct answer is-
F1 - AaBb (lacerate)
F2 - A_B_; A_bb; and aaB_ (lacerate)
- aabb (normal)
2. Two genes, with a dominant allele at either or both loci.
Explanation:
The given information gives THE following data:
Dominant: Lancerate leaves - AABB
Recessive: normal leaves - aabb
F1 has - all Lacerated leaves - AaBb
F2 by selfing F1:
AB Ab aB ab
AB AABB AABb AaBB AaBb
Ab AABb AAbb AaBb Aabb
aB AaBB AaBb aaBB aaBb
ab AaBb Aabb aaBb aabb
Here, 15/16 = lacerate which is 0.94 which is equal to the value of lacerate given in the question - 249/265 = 0.94
And normal 1/16 = 0.062 is almost same as 16/265 = 0.060
Thus, the genotypes of -
F1 - AaBb (lacerate)
F2 - A_B_; A_bb; and aaB_ (lacerate)
- aabb (normal)
(a) solute = substance (solid or liquid) in lesser amount, which will [dis]solve into the solvent
(b) solvent = substance (liquid) in larger amount, which [dis]solves the solvent
it's dissolvability is called "solvency"
water is known as the universal solvent because it is abundant on Earth and has a high solvency
(c) solution = the combination of solvent + solute
depending on the saturation of solute within solvent, the solution may appear clear, like the solvent
**think of warm sugar-water (solution), when all the sugar (solute) dissolves into the water (solvent), the solute seems to have disappeared
Smooth ER<span>, by contrast, is not associated with </span>ribosomes<span>, and its </span>functions<span> differ. The </span>smooth ER<span> is involved in the synthesis of lipids, including cholesterol and phospholipids, which are used in the production of </span>new<span> cellular membrane.</span>
