What is the electric force acting between two charges of 0.0042 C and −0.0050 C that are 0.0030 m apart?
1 answer:
Answer:
A.−2.1 × 10^10 N
Explanation:
Using the formula;
E = k Q1Q2/d²
Where;
E is the electrical force
k is the constant
Q1, Q2 are the two charges and
d is the distance between the two charges
Therefore;
E = (9 x 10^9) × (0.0042) × (-0.0050) / (0.0030)²
= -2.1 x 10^10 N
Therefore; electrical force acting between the two charges is -2.1 x 10^10 N.
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P=mv
0.25v=0.05*500
v=100 m/s
Pretty fast...
E is correct because net force in the forward direction is greater
By chromatography it's the answer
Answer:
0-0 what is rhat supposed to mean. i dont think anyone can answer that lol
You are right :P
Apex Legends is good!
