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erastova [34]
3 years ago
15

You are standing 5 m from a loud machine. You move 10 m from the machine to help reduce the intensity of the sound. Calculate th

e change in the sound’s intensity.‏
Physics
1 answer:
Nadusha1986 [10]3 years ago
4 0

Explanation:

realy sorry but i don't know pardon mr for this

soooooooooooorrryyyyyy

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Does peer pressure affect your physical activity routine? Describe this peer pressure and tell whether it is positive or negativ
Alexxx [7]
Yes, peer pressure affects one's physical activity routine. It can do so both negatively and positively. For instance, if one is pressured to do drugs when around their peers, it would most likely lead to an addiction that lasts even when they are not with those people anymore. However, from a positive viewpoint, one's peers could also pressure them to do something productive, such as trying a new beneficial activity that they are afraid of (ex. trying out for a talent show.) This could lead to a disruption in routine as that individual would begin practicing for said talent show. Hence, peer pressure can be both negative and positive, but in both instances, it changes the routine of the individual effected. 
4 0
3 years ago
Read 2 more answers
What are the rules for setting up an integral of rotation?
Angelina_Jolie [31]

Setting up an integral of rotation is used as a method of of calculating the volume of a 3D object formed by a rotated area of a 2D space. Finding the volume is similar to finding the area, but there is one additional component of rotating the area around a line of symmetry.

<span>First the solid of revolution should be defined. The general  function is y=f(x), on an interval [a,b].</span>

Then the curve is rotated about a given axis to get the surface of the solid of revolution. That is the integral of the function.

<span>It all depends of the function f(x), which must be known in order to calculate  the integral.</span>

3 0
3 years ago
Our eyes can see light with an angular resolution of about 1’—equivalent to about a third of a millimeter at arm’s length. Suppo
olya-2409 [2.1K]

Answer:

We would not be able to make our way around the earth's surface, to read, to sculpt or to create technology because we cannot see!

Explanation:

The minimum angular separation that can be distinguished by an eye gives the angular resolution of the eye.

Given that the Angular resolution with infrared radiation is = 1.0^0 equal to 60'

This resolution is very much greater than that of the eye (1')

The angular resolution that our eyes can see is about  \frac{1}{3}mm  at arms length

Angular resolution of infrared = \frac{1}{3} * 60 = 20mm  at arms length

We therefore cannot read, sculpt or create technology because we cannot see.

7 0
3 years ago
At which point on this electric field will a test charge show the maximum strength?
Juli2301 [7.4K]

Answer:

A

Explanation:

The figure shows the electric field produced by a spherical charge distribution - this is a radial field, whose strength decreases as the inverse of the square of the distance from the centre of the charge:

E\propto \frac{1}{r^2}

More precisely, the strength of the field at a distance r from the centre of the sphere is

E=k\frac{Q}{r^2}

where k is the Coulomb's constant and Q is the charge on the sphere.

From the equation, we see that the field strength decreases as we move away from the sphere: therefore, the strength is maximum for the point closest to the sphere, which is point A.

This can also be seen from the density of field lines: in fact, the closer the field lines, the stronger the field. Point A is the point where the lines have highest density, therefore it is also the point where the field is strongest.

8 0
3 years ago
FASTTT FOR BRAINLIST
telo118 [61]
The answer should be A?
7 0
2 years ago
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