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3 years ago

Which of the following compounds contains the Lead (II) ion? PbO PbCl4 Pb2O Pb2S

2 answers:

6 0

<span>PbO Let's look at each of the 4 compounds and see what's needed. PbO. * Oxygen has a valance shell that's missing 2 electrons and wants to get those 2 elections. Lead donates them, so you have a Lead (II) ions. This is a correct choice. PbCl4 * Chlorine wants to grab 1 electron to fill it's valance shell and Lead donates that election. However, there's 4 chlorine atoms and every one of them wants and electron, and lead is donating all 4 of the desired electrons making the Lead (IV) ion. So this is a bad choice. Pb2O * Oxygen still wants 2 electrons and gets them from the lead. But there's 2 lead atoms and each of them donates 1 election making for 2 Lead(I) ions. So this too is a bad choice. Pb2S * Sulfur is in the same column of the periodic table as oxygen and if this compound were to exist would have similar properties as Pb2O and would have Lead(I) ions. So this is a bad choice.</span>

nikitadnepr [17]3 years ago

4 0

1) A
2) B
3) A ---->your question
4) C

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Which bond has the greatest ionic character? A) H-Cl B) H-F c) H-O d) H-N

Len [333]

I really hope that this helps. H-F because the difference in electronegativity is the greatest, about 1.9 on the Pauling scale. The term means which bond has the greatest polarity and is thus most similar to an ionic bond, which involves the transfer of an electron (in opposition to covalent bonds, which share electrons). It is H-F because out of all the atoms here bonded with H, ie hydrogen, F is the most electronegative which means it can pull the bonded electrons to itself more than can Cl, O, and N. <span>That means a stronger polarization of the electron cloud forming the bond with hydrogen and therefore a stronger ionic character.</span>

5 0

3 years ago

What is the wavelength of light emitted when the electron in a hydrogen atom undergoes transition from an energy level with n =

Lady bird [3.3K]

Answer:

$4.86\times10^{-7}\ \text{m}$

Explanation:

R = Rydberg constant = $1.09677583\times 10^7\ \text{m}^{-1}$

$n_1$ = Principal quantum number of an energy level = 2

$n_2$ = Principal quantum number of an energy level for the atomic electron transition = 4

Wavelength is given by the Rydberg formula

$\lambda^{-1}=R\left(\dfrac{1}{n_1^2}-\dfrac{1}{n_2^2}\right)\\\Rightarrow \lambda^{-1}=1.09677583\times 10^7\left(\dfrac{1}{2^2}-\dfrac{1}{4^2}\right)\\\Rightarrow \lambda=\left(1.09677583\times 10^7\left(\dfrac{1}{2^2}-\dfrac{1}{4^2}\right)\right)^{-1}\\\Rightarrow \lambda=4.86\times10^{-7}\ \text{m}$

The wavelength of the light emitted is $4.86\times10^{-7}\ \text{m}$ .

6 0

3 years ago

Osmium: atomic number

bonufazy [111]

Osmium atomic number is 76

7 0

3 years ago

If you reacted 93.7 grams of iron with excess copper sulfate solution, what mass of copper would you expect to make? you may nee

Mariana [72]

Answer is although the question should have 3 significant figures.

<h3>What is significant figures?</h3>

Chemical equation

Fe + CuSO4 --> Cu + FeSO4

It is already balanced

Molar ratios

1 mol Fe : 1 mol CuSO4 : 1 mol Cu : 1 mol FeSO4

atomic masses of Fe and Cu

Fe: 55.8 g/mol

Cu: 63.5 g/mol

number of moles of Fe

number of moles = mass in grams / atomic mass = 93.7 g / 55.8 g/mol = 1.679 mol

number of moles of Cu:

1 mol Fe / 1 mol Cu => 1.679 mol Fe / 1.679 mole Cu

mass of Cu in 1.679 moles Cu

mass = atomic mass * number of atoms = 63.5 g/mol * 1.679 moles = 106.6 g = 107 rounded to 3 significant figures.

To learn more about significant figures, refer to:

brainly.com/question/24491627

#SPJ4

3 0

2 years ago

“Fe(NO3)3” is a...

ioda

Answer:

1. Fe(NO3)3 is C. Chemical formula

2. Manganese Sulphate is C. Name

3. Zn is C. Symbol

Hope this helps!

3 0

4 years ago