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Leni [432]
3 years ago
15

A photon of green light strikes an unknown metal and an electron is emitted. The voltage is set to 2 volts. The electron cannot

make the journey to the second plate. What can be said about a similar experiment done with violet light? A. An electron may or may not be emitted in the second experiment. It cannot be determined. B. An electron will be emitted in the second experiment, but it cannot be determined whether it will reach the second plate. C. An electron will be emitted in the second experiment, and it will make it to the second plate. D. An electron will not be emitted in the second experiment.
Chemistry
1 answer:
SVETLANKA909090 [29]3 years ago
7 0

Answer:

The correct answer is:

An electron will be emitted in the second experiment, but it cannot be determined whether it will reach the second plate.

Explanation:

In fact, violet has higher frequency than green light. This means that photons on violet carry more energy than photons of green light (remember that the energy of a photon is proportional to it's frequency:

e = hf

, so when they hit the surface of the metal, more energy is transferred to the electrons. The electron was already emitted with green light, so it must be emitted with also violet light, given the more energy transferred.

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Fe(s) + CuSO4(aq) <===> Cu(s) + FeSO4(aq)
Ludmilka [50]

Answer : The original concentration of copper (II) sulfate in the sample is, 5.6\times 10^{-1}g/L

Explanation :

Molar mass of Cu = 63.5 g/mol

First we have to calculate the number of moles of Cu.

Number of moles of Cu = \frac{\text{Mass of Cu}}{\text{Molar mass of Cu}}=\frac{89\times 10^{-3}g}{63.5g/mol}=1.40\times 10^{-3}mole

Now we have to calculate the number of moles of CuSO_4

Number of moles of Cu = Number of moles of CuSO_4

Number of moles of CuSO_4 = 1.40\times 10^{-3}mole

Now we have to calculate the molarity of CuSO_4

\text{Molarity}=\frac{\text{Moles of }CuSO_4\times 1000}{\text{Volume of solution (in mL)}}

Now put all the given values in this formula, we get:

\text{Molarity}=\frac{1.40\times 10^{-3}mole\times 1000}{400.mL}=0.0035M

To change mol/L into g/L, we need to multiply it with molar mass of CuSO_4

Molar mass of CuSO_4= 159.609 g/mL

Concentration in g/L = 0.0035M\times 159.609g/mol=0.5586g/L\approx 5.6\times 10^{-1}g/L

Thus, the original concentration of copper (II) sulfate in the sample is, 5.6\times 10^{-1}g/L

3 0
3 years ago
Be sure to answer all parts. Write an unbalanced equation to represent each of the following reactions: Do not include phase abb
Eva8 [605]

<u>Answer:</u> The unbalanced chemical equations are written below.

<u>Explanation:</u>

An unbalanced chemical equation is defined as the equation in which total number of individual atoms on the reactant side is not equal to the total number of individual atoms on the product side. These equations does not follow law of conservation of mass.

  • <u>For a:</u>

The chemical equation for the reaction of nitrogen gas and oxygen gas follows:

N_2+O_2\rightarrow NO_2

The product formed is nitrogen dioxide.

  • <u>For b:</u>

The chemical equation for the decomposition of dinitrogen pentaoxide follows:

N_2O_5\rightarrow N_2O_4+O_2

The product formed is dinitrogen tetroxide and oxygen gas.

  • <u>For c:</u>

The chemical equation for the reaction of ozone to oxygen gas follows:

O_3\rightarrow O_2

The product formed is oxygen gas.

  • <u>For d:</u>

The chemical equation for the reaction of chlorine and sodium iodide follows:

Cl_2+NaI\rightarrow NaCl+I_2

The product formed is sodium chloride and iodine gas

  • <u>For e:</u>

The chemical equation for the reaction of magnesium and oxygen gas follows:

Mg+O_2\rightarrow MgO

The product formed is magnesium oxide

3 0
3 years ago
A dark purple liquid is diluted by adding water.
alexandr402 [8]

Answer: The process is diffusion.

Explanation:

a dark liquid will have the highest concentration of dark purple atoms/molecules so it gives a concentrated colour.

when water is added to it, the colourless water molecules fill up the gaps between the purple particles and so their colour fades and becomes lighter and lighter as we add more water. see the image attached where imagine the red particles are water and the blue particles are purple particles. thats why the colour fades.

6 0
1 year ago
A sodium atom can easily lose an electron. What happens to this electron?
meriva

Answer:

A.it is converted into thermal energy

4 0
3 years ago
Shifts in the rock layer locations cannot account for gaps in the rock record<br><br> true or false
vivado [14]

Answer: That would be false because it is the contact between two layers representing a gap in the geologic record, usually from the erosion of the layers which would normally be expected to appear.

Explanation:

Have a good day

I hope this helps if not sorry :(

Stay motivated

4 0
3 years ago
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