Question

A photon of green light strikes an unknown metal and an electron is emitted. The voltage is set to 2 volts. The electron cannot make the journey to the second plate. What can be said about a similar experiment done with violet light? A. An electron may or may not be emitted in the second experiment. It cannot be determined. B. An electron will be emitted in the second experiment, but it cannot be determined whether it will reach the second plate. C. An electron will be emitted in the second experiment, and it will make it to the second plate. D. An electron will not be emitted in the second experiment.

Answer 1

Answer:

The correct answer is:

An electron will be emitted in the second experiment, but it cannot be determined whether it will reach the second plate.

Explanation:

In fact, violet has higher frequency than green light. This means that photons on violet carry more energy than photons of green light (remember that the energy of a photon is proportional to it's frequency:

$e = hf$

, so when they hit the surface of the metal, more energy is transferred to the electrons. The electron was already emitted with green light, so it must be emitted with also violet light, given the more energy transferred.