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andreyandreev [35.5K]
3 years ago
13

BRAINLIESTTT ASAP!! PLEASE HELP ME :)

Chemistry
1 answer:
lord [1]3 years ago
3 0
There ya go.. i hope this helps! sorry if it doesn't!

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What is the molarity of the solution with a volume of 23.47 Liters and 14.968 moles?
MrMuchimi

Answer:

0.6378 M

Explanation:

Molarity is defined by Moles per liter.

Plugging the given information in, we get (14.968 moles)/(23.47 L) which comes out to be about 0.6378 M

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The following reaction between ethyl alcohol and ethyl bromide forms diethyl ether via a substitution reaction (followed by depr
m_a_m_a [10]

Answer:

see explanation below

Explanation:

The question is incomplete. The missing parts are a) determine the electrophylic site. b) determine the nucleophylic site.

In order to do this, we need to write the reaction and do the mechanism. The nucleophylic site will be the site where the nucleophyle attacks to form the product. In this case the site is the carbon next to the bromine. In this place the Oxigen which is the nucleophyle goes. The electrophyle is the site where one atom substract to complete it's charges. In this case, the electrophyle is usually the hydrogen, so the site will be next to the oxygen after the nucleophyle attack.

You can see it better in the attached picture.

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The specific heat of zinc is 0.39 j/g*��
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The total volume of hydrogen gas needed to fill the hindenburg was 2.00 × 108 l at 1.00 atm and 25.° c. How much energy was evol
Step2247 [10]

Answer : The energy evolved when it burned was, -2.337\times 10^9KJ

Solution :

First we have to calculate the moles of hydrogen gas by using ideal gas equation.

PV=nRT

where,

P = pressure of gas = 1 atm

V = volume of gas = 2\times 10^8L

T = temperature of gas = 25^oC=273+25=298K

R = gas constant = 0.0821 Latm/moleK

n = number of moles of gas

Now put all the given values in the above formula, we get the moles of hydrogen gas.

(1atm)\times (2\times 10^8L)=n\times (0.0821Latm/moleK)\times (298K)

n=8.174\times 10^6moles

Now we have to calculate the amount of energy evolved.

The combustion reaction of hydrogen will be,

H_2(g)+\frac{1}{2}O_2(g)\rightarrow H_2O(l)

The enthalpy of combustion of hydrogen is -286 KJ/mole. (standard value)

As 1 mole of hydrogen gas burned it evolved energy = -286 KJ

So, 8.174\times 10^6moles of hydrogen gas burned it evolved energy = (8.174\times 10^6)\times (-286)=-2.337\times 10^9KJ

Therefore, the energy evolved when it burned was, -2.337\times 10^9KJ

5 0
3 years ago
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