Question

The specific heat of zinc is 0.39 j/g*��

Answer 1

Answer : The amount of energy needed are, 464.1 J and the value is positive that means the energy is absorbed.

Solution :

Formula used :

$Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})$

where,

Q = energy gained or absorbed = ?

m = mass of zinc = 34 g

c = specific heat of zinc = $0.39J/g^oC$      

$\Delta T=\text{Change in temperature}$  

$T_{final}$ = final temperature = $57^oC$

$T_{initial}$ = initial temperature = $22^oC$

Now put all the given values in the above formula, we get the energy gained or absorbed.

$Q=34g\times 0.39J/g^oC\times (57-22)^oC$

$Q=464.1J$

Therefore, the amount of energy needed are, 464.1 J and the value is positive that means the energy is absorbed.

Answer 2

I just did this and the correct answer was 464.1 J, absorbed