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liq [111]
4 years ago
5

Plutonium-239 is used in nuclear bombs determine the number of protons and neutrons in plutonium-239 and enter its symbol in the

form azx.
Chemistry
1 answer:
Romashka-Z-Leto [24]4 years ago
8 0

Plutonium-239 is used in nuclear bombs, here 239 is its mass number. For an atom, mass number is equal to sum of number of protons and neutrons.

Thus,

A=n+p=239...... (1)

From periodic table, the atomic number of plutonium is 94 which is equal to number of electron and proton in an atom.

Thus,

Z=p=94

Putting the value of p in equation (1)

n=239-94=145

The symbol is as follows:

_{Z}^{A}\textrm{X}

Here, Z is atomic number, A is mass number and X is atom symbol thus, symbol for plutonium will be:

_{94}^{239}\textrm{Pu}

Therefore, number of protons, neutrons and symbol is 94, 145 and  _{94}^{239}\textrm{Pu}respectively.

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How many grams of solute are needed to make 2.50 L of a 1.75 M solution of Ba(NO3)2?
Eddi Din [679]

1143.4grams of solute are needed to make 2.50L of a 1.75M solution of Ba(NO3)2. Details about molarity can be found below.

<h3>How to calculate mass?</h3>

The mass of a substance can be calculated by multiplying the number of moles by its molar mass.

However, the number of moles can be calculated by using the following formula:

Molarity = no of moles ÷ volume

no of moles = 1.75 × 2.5

no of moles = 4.38mol

molar mass of Ba(NO3)2 = 261.34g/mol

mass of Ba(NO3)2 = 261.34 × 4.38

mass of Ba(NO3)2 = 1143.4grams.

Therefore, 1143.4grams of solute are needed to make 2.50L of a 1.75M solution of Ba(NO3)2.

Learn more about mass at: brainly.com/question/19694949

3 0
2 years ago
What is in the solar system?
Zina [86]

Answer:

All of the above

Explanation:

All of this is in the solar system.

7 0
3 years ago
Read 2 more answers
What will be the volume occupied by 2.5 moles of nitrogen gas exerting 1.75 atm of pressure at 475K?
Marina86 [1]

Answer:

THE VOLUME OF THE NITROGEN GAS AT 2.5  MOLES , 1.75 ATM AND 475 K IS 55.64 L

Explanation:

Using the ideal gas equation

PV = nRT

P = 1.75 atm

n = 2.5 moles

T = 475 K

R = 0.082 L atm/mol K

V = unknown

Substituting the variables into the equation we have:

V = nRT / P

V = 2.5 * 0.082 * 475 / 1.75

V = 97.375 / 1.75

V = 55.64 L

The volume of the 2.5 moles of nitrogen gas exerted by 1.75 atm at 475 K is 55.64 L

6 0
3 years ago
The natural tendence of an object to resist change in its state of motion is:
melisa1 [442]

Inertia. Inertia is the natural tendency of bodies to remain in their states of either rectilinear or resting motion.

5 0
3 years ago
A 1.800-g sample of solid phenol (C6H5OH(s)) was burned in a bomb calorimeter whose total heat capacity is 11.66 kJ/?C. The temp
vichka [17]

Answer:

The balanced chemical equation:

C_6H_5OH(s)+7O_2(g)\rightarrow 6CO_2(g)+3H_2O(g)

Heat of combustion per gram of phenol is 32.454 kJ/g

Heat of combustion per gram of phenol is 3,050 kJ/mol

Explanation:

C_6H_5OH(s)+7O_2(g)\rightarrow 6CO_2(g)+3H_2O(g)

Heat capacity of calorimeter = C = 11.66 kJ/°C

Initial temperature of the calorimeter = T_1= 21.36^oC

Final temperature of the calorimeter = T_2= 26.37^oC

Heat absorbed by calorimeter = Q

Q=C\times \Delta T

Heat released during reaction = Q'

Q' = -Q ( law of conservation of energy)

Energy released on combustion of 1.800 grams of phenol = Q' = -(58.4166 kJ)

Heat of combustion per gram of phenol:

\frac{Q'}{1.800 g}=\frac{-58.4166 kJ}{1.800 g}=32.454 kJ/g

Molar mass of phenol = 94 g/mol

Heat of combustion per gram of phenol:

\frac{Q'}{\frac{1.800 g}{94 g/mol}}=\frac{-58.4166 kJ\times 94 g/mol}{1.800 g}=3,050 kJ/mol

3 0
3 years ago
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