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xz_007 [3.2K]
3 years ago
13

Match the chemical with the statement that best describes the observed change in the rate of the reaction when the concentration

of that chemical was changed and other chemicals are held constant.
A. the H2O2 concentration is doubled:

B. the KCl concentration is doubled:

C. the catalyst concentration is doubled:

Possible Answers:

Match the chemical with the statement that best describes the observed change in the rate of the reaction when the concentration of that chemical was changed and other chemicals are held constant.

the H2O2 concentration is doubled

[ Choose ] the rate of oxygen collected is approximately half as fast there is little or no effect on the rate of oxygen collection the rate of oxygen collected is approximately twice as fast the rate of oxygen collected is approximately four times slower the rate of oxygen collected is approximately four times faster

the KCl concentration is doubled:

the rate of oxygen collected is approximately half as fast there is little or no effect on the rate of oxygen collection the rate of oxygen collected is approximately twice as fast the rate of oxygen collected is approximately four times slower the rate of oxygen collected is approximately four times faster

the catalyst concentration is doubled
Chemistry
1 answer:
maria [59]3 years ago
8 0

Answer:

Explanation:

When the amount of H2O2 is doubled while KI is kept constant, the rate of reaction doubles.

When the amount of KI is doubled and the amount of H2O2 is halved, the rate stays nearly constant.

2H2O2 (aq) → O2(g) + 2H2O (l) ------------- first order kinetics reaction.

Catalysts are KI, FeCl3 only, KCl is not a catalyst. Order: KI < MnO2 < Pb < FeCl3.

H2O2 + I– -> IO– + H2O (Step 1)

H2O2 + IO– -> I– + H2O + O2 (Step 2)

It can be seen that the iodine ion (provided by the KI solution) is a product as well as a reactant.

02(g)2Fe? (aq) + 2 H(a) 2 H 2 Fe3 (aq) H2O2(aq) + 2 Fe,Taq) H02(aq) 2 Fe (aq) 2 H (aq)

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The British gold sovereign coin is an alloy of gold and copper having a total mass of 7.988 g, and is 22-karat gold.
azamat

Answer:

(a) m_{gold}=7.322g

(b)

V_{gold}=0.379cm^3

V_{copper}=0.122cm^3

(c) \rho _{coin}=15.94g/cm^3

Explanation:

Hello,

(a) In this case, with the given formula we easily compute the mass of gold contained in the sovereign  as shown below:

m_{gold}=\frac{m_{tota}*karats}{24}=\frac{7.988g*22}{24}=7.322g

(b) Now, by knowing the density of gold and copper, 19.32 and 8.94 g/cm³ respectively, we compute each volume, by also knowing that the rest of the coin contains copper:

V_{gold}=\frac{m_{gold}}{\rho_{gold}} =\frac{7.322g}{19.32g/cm^3}=0.379cm^3

m_{copper}=7.988g-7.322g=1.09g\\V_{copper}=\frac{m_{copper}}{\rho_{copper}}=\frac{1.09g}{8.94g/cm^3}  \\\\V_{copper}=0.122cm^3

(c) Finally, the volume is computed by dividing the total mass over the total volume containing both gold and copper:

\rho _{coin}=\frac{m_{total}}{V_{gold}+V_{copper}}=\frac{7.988 g}{0.379cm^3+0.122cm^3}\\  \\\rho _{coin}=15.94g/cm^3

Best regards.

3 0
3 years ago
Read 2 more answers
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