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xz_007 [3.2K]
2 years ago
13

Match the chemical with the statement that best describes the observed change in the rate of the reaction when the concentration

of that chemical was changed and other chemicals are held constant.
A. the H2O2 concentration is doubled:

B. the KCl concentration is doubled:

C. the catalyst concentration is doubled:

Possible Answers:

Match the chemical with the statement that best describes the observed change in the rate of the reaction when the concentration of that chemical was changed and other chemicals are held constant.

the H2O2 concentration is doubled

[ Choose ] the rate of oxygen collected is approximately half as fast there is little or no effect on the rate of oxygen collection the rate of oxygen collected is approximately twice as fast the rate of oxygen collected is approximately four times slower the rate of oxygen collected is approximately four times faster

the KCl concentration is doubled:

the rate of oxygen collected is approximately half as fast there is little or no effect on the rate of oxygen collection the rate of oxygen collected is approximately twice as fast the rate of oxygen collected is approximately four times slower the rate of oxygen collected is approximately four times faster

the catalyst concentration is doubled
Chemistry
1 answer:
maria [59]2 years ago
8 0

Answer:

Explanation:

When the amount of H2O2 is doubled while KI is kept constant, the rate of reaction doubles.

When the amount of KI is doubled and the amount of H2O2 is halved, the rate stays nearly constant.

2H2O2 (aq) → O2(g) + 2H2O (l) ------------- first order kinetics reaction.

Catalysts are KI, FeCl3 only, KCl is not a catalyst. Order: KI < MnO2 < Pb < FeCl3.

H2O2 + I– -> IO– + H2O (Step 1)

H2O2 + IO– -> I– + H2O + O2 (Step 2)

It can be seen that the iodine ion (provided by the KI solution) is a product as well as a reactant.

02(g)2Fe? (aq) + 2 H(a) 2 H 2 Fe3 (aq) H2O2(aq) + 2 Fe,Taq) H02(aq) 2 Fe (aq) 2 H (aq)

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Sindrei [870]

Aldol condensation involves the reaction of an acid or base with a carbonyl group producing a nucleophile that attacks another carbonyl compound  to yield a β-hydroxyaldehyde or β-hydroxyketone compound.

<h3>What is aldol condensation?</h3>

The aldol condensation is a reaction in organic chemistry in which there is a reaction between an acid or base and a carbonyl group which then serves as the nucleophile that attcks a second carbonyl to yield a β-hydroxyaldehyde or β-hydroxyketone compound.

The aldol condensation may be acid catalysed or base catlysed. The question is incomplete hence the complete mechanimsms can not be decuced.

Learn more about aldol condensation: brainly.com/question/9415260

3 0
2 years ago
Many medical devices are designed using the electromagnetic spectrum. Which type of electromagnetic wave has enough energy to ki
tresset_1 [31]
Gamma rays because the kill every living cell and they have the shortest waves that are dangerous
4 0
3 years ago
A student experimentally obtained the density of osmium the densest element as 22.57g/cm3 the density of osmium is reported to b
Airida [17]

Answer:

The answer to your question is: % error = 0.4

Explanation:

Data

real value = 22.48%

estimated value = 22.57 %

Formula

% error = |real value - estimated value|/real value x 100

%error = |22.48 - 22.57|/22.48 x 100

% error = |-0.09|/22.48 x 100

%error = 0.09/22.48 x 100

% error = 0.004 x 100

% error = 0.4

3 0
3 years ago
When you have finished adding the necessary amount of NaOH to your beaker, what color will the litmus paper turn?
Svetllana [295]

<u>Answer:</u> The red litmus paper turns blue on dipping in NaOH solution.

<u>Explanation:</u>

Litmus paper is the indicator that detects the nature of the solution, whether it is acidic or basic.

There are 2 types of litmus paper:

  • <u>Red litmus paper:</u> This paper will turn blue if it is dipped in basic solution and will remain as such if it is dipped in acidic solution.
  • <u>Blue litmus paper:</u> This paper will turn red if it is dipped in acidic solution and will remain as such if it is dipped in basic solution.

NaOH is a strong base, so when a red litmus paper is dipped in the beaker having necessary amount of NaOH, the red litmus paper turns into blue.

7 0
3 years ago
Complete combustion of a 17.12mg sample of xylene In oxygen yielded 56.77mg
Veronika [31]

Xylene moles =\frac{17.12}{106.16×1000}=0.00016moles=

106.16×1000

17.12

=0.00016moles

Moles of CO_2 =\frac{56.77}{44.01×1000}=0.0013CO

2

=

44.01×1000

56.77

=0.0013

Moles of H_2O= =\frac{14.53}{18.02×1000}=0.0008H

2

O==

18.02×1000

14.53

=0.0008

Moles ratios

\frac{0.0013}{0.0008}=1.625

0.0008

0.0013

=1.625

\frac{0.0008}{0.0008}=1

0.0008

0.0008

=1

Hence molecular fomula

The empirical formula is C 4H 5.

The molecular formula C8H10

8 0
2 years ago
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