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topjm [15]
3 years ago
14

The specific heat for liquid ethanol is 2.46 J/(g•°C). When 210 g of ethanol is cooled from

Chemistry
1 answer:
avanturin [10]3 years ago
3 0

Answer:

a) heat it from 23.0 to 78.3

q = (50.0 g) (55.3 °C) (2.46 J/g·°C) =  

b) boil it at 78.3

(39.3 kJ/mol) (50.0 g / 46.0684 g/mol) =  

c) sum up the answers from the two calculations above. Be sure to change the J from the first calc into kJ

Explanation:

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Softa [21]

Answer:

1. HBr>HCl> H2S >BH3

2.K_a1 very large — H2SO4

K_a1= 1.7 x 10^−2 — H2SO3

K_a1 = 1.7 x 10^−7 — H2S

Explanation:

As one goes down a row in the Periodic Table the properties that determine the acid strength can be observed.

The atoms get larger in radius meaning that in strength, the strength of the bonds get weaker, conversely meaning that the acids get stronger.

For the halogen-containing acids above following the rows and periods, HBr has the strongest bond and is the strongest acid and others follow in this order.

HBr>HCl> H2S >BH3

Acid Dissociation Constant provides us with information known as the ionization constant which comes in handy to measure the acid's strength. The meaning of the proportions are thus, the higher the Ka value, the stronger the acid i.e. it liberates more number of hydrogen ions per mole of acid in solution.

In solution strong acids completely dissociate hence, the value of dissociation constant of strong acids is very high.

Following the cues above on Ka;

K_a1 very large — H2SO4

K_a1= 1.7 x 10^−2 — H2SO3

K_a1 = 1.7 x 10^−7 — H2S

5 0
3 years ago
Inertia is _____ to mass
Arisa [49]

Answer:

directly proportional

6 0
3 years ago
Read 2 more answers
1.) is H2SO4 a sulfuric acid or a sulfurous acid?
Lorico [155]
1) is sulfuric acid
2)is nitrous acid
3)is hydrochlorous acid
4)is hydrobromous acid
5)is hydrophosphoric acid
6)is fluoric acid
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3 0
3 years ago
Given the following reaction: NH4SH (s) <--> NH3 (g) + H2S (g) If we start
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Answer:

D. 0.3 M

Explanation:

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Initial concentration              0.085mol/0.25L             0                 0

Change in concentration     -0.2M                               +0.2 M        +0.2M

Equilibrium               0.035mol/0.25 L=0.14M             0.2M           0.2M

concentration

Change in concentration (NH4SH) = (0.085-0.035)mol/0.25L =0.2M

K = [NH3]*[H2S]/[NH4SH] = 0.2M*0.2M/0.14M ≈ 0.29 M ≈ 0.3M

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What causes ocean water near the equator to be warmer than ocean water farther north
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Because the water near the equator gets more direct sunlight.
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