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When you arrange the N points in sequence around the polygon (clockwise or counterclockwise), the area is half the magnitude of the sum of the determinants of the points taken pairwise. The N determinants will also include the one involving the last point and the first one.
For example, consider the vertices of a triangle: (1,1), (2,3), (3,-1). Its area can be computed as
(1/2)*|(1*3-1*2) +(2*-1-3*3) +(3*1-(-1)*1)|
= (1/2)*|1 -11 +4| = 3
For example, consider the vertices of a triangle: (1,1), (2,3), (3,-1). Its area can be computed as
(1/2)*|(1*3-1*2) +(2*-1-3*3) +(3*1-(-1)*1)|
= (1/2)*|1 -11 +4| = 3
Using it's concept, it is found that the graph has no horizontal asymptote.
<h3>What are the horizontal asymptotes of a function f(x)?</h3>The horizontal asymptote is the value of f(x) as x goes to infinity, as long as this value is different of infinity.
In this problem, we have that:
- The function is undefined for x < 0, hence
is undefined.
- For x > 0, the funciton goes to infinity, hence
.
Thus, the graph has no horizontal asymptote.
More can be learned about horizontal asymptotes at brainly.com/question/16948935
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