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3 years ago

The substance that does the dissolving in a solution is called a(n) __________.

Chemistry

2 answers:

leonid [27]3 years ago

7 0

Easy, the answer is (C)

sergey [27]3 years ago

6 0

The answer is C solvent

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Solid sodium reacts with liquid water to form hydrogen gas according to the equation 2 Na(s) + 2 H₂O(l) → 2 NaOH(aq) + H₂(g) Wha

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Answer:

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4 years ago

Convert 31.9 g of N2 to moles

pashok25 [27]

Answer: 1.14mol

Nitrogen molar mass=14g/mol

N2 molar mass=14*2=28g/mol

31.9g(1/28)=1.14mol N2

5 0

4 years ago

Which of two curves exhibits exponential growth

ExtremeBDS [4]

Answer:

The top curve/graph is exponential growth. All exponential growth graphs look like a J in a way! Hope that helped

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4 years ago

A balloon contains 2.0 L of air at 101.5 kPa . You squeeze the balloon to a volume of 0.25 L.

8_murik_8 [283]

<h3>Answer:</h3>

812 kPa

<h3>Explanation:</h3>

According to Boyle's law pressure and volume of a fixed mass are inversely proportional at constant absolute temperature.

Mathematically, $P\alpha \frac{1}{V}$

At varying pressure and volume;

P1V1=P2V2

In this case;

Initial volume, V1 = 2.0 L

Initial pressure, P1 = 101.5 kPa

Final volume, V1 = 0.25 L

We are required to determine the new pressure;

$P2=\frac{P1V1}{V2}$

Replacing the known variables with the values;

$P2=\frac{(101.5)(2.0L)}{0.25L}$

= 812 kPa

Thus, the pressure of air inside the balloon after squeezing is 812 kPa

8 0

3 years ago

An element, X, can form a chloride (XCl3) and an iodide (XI3). The chloride can be converted quantitatively into the iodide when

Arlecino [84]

Answer : The chemical symbol for this element is, (La)

Explanation : Given,

Mass of $XCl_3$ = 0.760 g

Mass of $XI_3$ = 1.610 g

The given chemical reaction is:

$2XCl_3+3I_2\rightarrow 2XI_3+3Cl_2$

First we have to calculate the moles of $XCl_3$ and $XI_3$ .

$\text{Moles of }XCl_3=\frac{\text{Mass of }XCl_3}{\text{Molar mass of }XCl_3}$

Molar mass of Cl = 35.5 g/mole

Let the molar mass of element 'X' be, M

$\text{Moles of }XCl_3=\frac{0.760}{[M+3(35.5)]}$

and,

$\text{Moles of }XI_3=\frac{\text{Mass of }XI_3}{\text{Molar mass of }XI_3}$

Molar mass of I = 126.9 g/mole

Let the molar mass of element 'X' be, M

$\text{Moles of }XI_3=\frac{1.610}{[M+3(126.9)]}$

From the balanced chemical reaction we conclude that,

The moles of ratio of $XCl_3$ and $XI_3$ is, 1 : 1

That means,

$\frac{0.760}{[M+3(35.5)]}=\frac{1.610}{[M+3(126.9)]}$

$\frac{0.760}{[M+106.5]}=\frac{1.610}{[M+380.7]}$

$M=138.667g/mol$

From this we conclude that the element (X) is lanthanum (La) that has molecular weight, 138.667 g/mol.

Hence, the chemical symbol for this element is, (La)

6 0

4 years ago