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3 years ago

Which ion is not an oxyanion? NO− SO4 2− CN− CO3 2−

Chemistry

1 answer:

dimulka [17.4K]3 years ago

3 0

Answer:

CN⁻

Explanation:

Oxyanion:

Oxyanion is the anion that have oxygen atom.

General formula:

The general formula for oxyanion is AₓOₓ⁻².

A = symbol of element combining with oxygen.

O = oxygen atom

z,x, = integers

a) = NO⁻

Its is an oxyanion because oxygen atom is present with nitrogen.

b) = SO₄⁻

It is an oxyanion because oxygen atom is present.

c) = CN⁻

This is not an oxyanion because there is no oxygen atom present.

d= CO₃²⁻

It is also an oxyanion because of presence of oxygen atom.

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2 Carbon (C) is found on the Periodic Table; however, Carbon Dioxide (CO2) is not. Why is this the case? А B с D

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Answer:

2 Carbon (C) is found on the Periodic Table; however, Carbon Dioxide (CO2) is not. Why is this the case? А B с D

A Only substances that cannot be broken down into simpler substances are found on the Periodic Table.

B Only gases are found on the Periodic Table.

C Only compounds are found on the Periodic Table.

D Compounds cannot be broken down into simpler substances.

Answer:

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2 years ago

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KiRa [710]

Answer:

62.15 m (squared)

Explanation:

We know that the Area of the square is 5.5 x 4= 22

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now 7.3 x 5.5 = 40.15

22 + 40.15 = 62.15 m (squared)

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3 years ago

Read 2 more answers

Sodium borohydride, NaBH4, and boron trifluoride, BF3, are compounds of boron. What are the shapes around boron in the borohydri

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Compound 1: Sodium borohydride
In sodium borohydride (NaBH4), B is a central metal.
Electronic configuration of B is 1s2 2s2 2p1.
B undergoes sp3 hybridization in NaBH4, to generate 4 hybrid orbitals. These hybrid orbitals, forms sigma bond with 4 'H' atoms. Due to this, the structure of sodium borohydride in tetrahedral.
........................................................................................................................

Compound 2: Boron trifluoride
In boron trifluoride (BF3), B is a central metal.
Electronic configuration of B is 1s2 2s2 2p1.
B undergoes sp2 hybridization in NaBH4, to generate 3 hybrid orbitals. These hybrid orbitals, forms sigma bond with 3 'H' atoms. Due to this, the structure of boron trifluoride is triangular planner.

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3 years ago

Read 2 more answers

The rate constant k for a certain reaction is measured at two different temperatures temperature 376.0 °c 4.8 x 108 280.0 °C 2.3

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Answer:

The activation energy for this reaction = 23 kJ/mol.

Explanation:

Using the expression,

$\ln \dfrac{k_{1}}{k_{2}} =-\dfrac{E_{a}}{R} \left (\dfrac{1}{T_1}-\dfrac{1}{T_2} \right )$

Where,

$k_1\ is\ the\ rate\ constant\ at\ T_1$

$k_2\ is\ the\ rate\ constant\ at\ T_2$

$E_a$ is the activation energy

R is Gas constant having value = 8.314×10⁻³ kJ / K mol

$k_2=2.3\times 10^8$

$T_2=280\ ^0C$

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15

So,

T = (280 + 273.15) K = 553.15 K

$T_2=553.15\ K$

$k_1=4.8\times 10^8$

$T_1=376\ ^0C$

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15

So,

T = (376 + 273.15) K = 649.15 K

$T_1=649.15\ K$

So,

$\left(\ln \left(\:\frac{4.8\times \:\:\:10^8}{2.3\times \:\:\:10^8}\right)\right)\:=-\frac{E_a}{8.314\times \:10^{-3}\ kJ/mol.K}\times \:\left(\frac{1}{649.15\ K}-\frac{1}{553.15\ K}\right)$

$E_a=-\frac{10^{-3}\times \:8.314\ln \left(\frac{10^8\times \:4.8}{10^8\times \:2.3}\right)}{-\frac{96}{359077.3225}}\ kJ/mol$

$E_a=-\frac{\frac{8.314\ln \left(\frac{4.8}{2.3}\right)}{1000}}{-\frac{96}{359077.3225}}\ kJ/mol$

$E_a=22.87\ kJ/mol$

The activation energy for this reaction = 23 kJ/mol.

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3 years ago