12 more than 8.2 times a number n

TotCo is developing a new deluxe baby bassinet. If the length of a newborn baby is normally distributed with a mean of 50 cm and

slavikrds [6]

Answer:

91.63 cm is the interior length of the bassinet to ensure that 99 percent of newborn babies will fit, with a safety margin of 15 cm on each end of the bassinet.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 50 cm

Standard Deviation, σ = 5 cm

We are given that the distribution of length of a newborn baby is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

P(X<x) = 0.99

We have to find the value of x such that the probability is 0.99

P(X < x)

$P( X < x) = P( z < \displaystyle\frac{x - 50}{5})=0.99$

Calculation the value from standard normal table, we have,

$P(z$

$\displaystyle\frac{x - 50}{5} = 2.326\\x = 61.63$

Thus, 99% of newborn babies will have a length of 61.63 cm or less.

There is a safety margin of 15 cm on each end of the bassinet

Length of bassinet =

$61+63 + 15 +15 = 91.63\text{ cm}$

6 0

3 years ago

What is the solution of 3+x-2/x-3<_4

VikaD [51]

Step-by-step explanation:

3+x-2/x-3<_4

cross multiply

3+x-2<_4(x-3)

3+x-2<_4x-12

1+x<_4x-12

collect like terms

1+12<_4x-x

13<_3x

divide both side by 3

13/3<_×

6.5<_x

3 0

3 years ago

Need help with geometry. Finding the slant height of a pyramid

Setler [38]

980 ÷ 14 = 70 In.

So, the answer is 70 in.

Hope This helps!~

4 0

3 years ago

Afla un numar,stiind ca: a)jumatatea treimii lui este 25; b)sfertul jumatatii lui este 48; c)treimea sfertului sau,marita cu 17

aalyn [17]

Answer:

(a) 150

(b) 384

(c) 84

(d) 261

(e ) 480

Step-by-step explanation:

(a)

Let 'a' be a number such that the half of his third is 25; i.e.

$\dfrac{1}{2}\times(\dfrac{1}{3}a)=25\\\\\dfrca{1}{2\times3}a=25\\\\\dfrac{1}{6}\times a=25\\\\a=25\times6\\\\a=150$

Hence, the number is 150.

(b)

Let 'b' be the number such that the quarter of his half is 48 i.e.

$\dfrac{1}{4}(\dfrac{1}{2}b)=48\\\\\dfrac{1}{8}b=48\\\\b=48\times8\\\\b=384$

Hence the number is 384.

(c)

Let 'c' be the number such that the third quarter or, increased by 17 is 80.

$\dfrac{3}{4}c+17=80\\\\\dfrac{3}{4}c=80-17\\\\\dfrac{3}{4}c=63\\\\c=\dfrac{63\times4}{3}\\\\c=\dfrac{252}{3}\\\\c=84$

Hence, the number is 84.

(d)

Let 'd' be the number such that its triplet, reduced by 28 is 755

$3d-28=755\\\\3d=755+28=783\\\\d=\dfrac{783}{3}\\\\d=261$

Hence the number is 261.

(e

Let 'e' be the number such that double his third, increased by 80 is 400.

$\\2\dfrac{1}{3}e+80=400\\\\\dfrac{2}{3}e=400-80=320\\\\e=\dfrac{320\times 3}{2}\\\\e=\dfrac{960}{2}\\\\e=480$

Hence, the value of the number is 480.

4 0

4 years ago

Jose ha encontrado varios insectos. Hay 10 menos saltamontes que grillos. Hay 5 menos grillos que margaritas. Si Jose ha encontr

rewona [7]

Answer: There are 5 grasshoppers, 15 crickets and 20 ladybugs

Step-by-step explanation:

The question in english is:

Jose has found several insects. There are 10 less grasshoppers than crickets. There are 5 less crickets than ladybugs. If Jose has found 5 grasshoppers, how many ladybugs did he find and how many crickets? Write two equations to solve the problem.

Let's tag grasshoppers with $g$ , crickets with $c$ and ladybugs with $c$ .