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2 years ago

Expand and simplify x(x+2)x+(x+3)

2 answers:

5 0

To start, first distribute the x's to their expressions. This would look like this:
(x*x+2*x)+(x*x+x*3)=x^2+2x+x^2+3x
Then, you combine like terms or simplify, and you get an answer of 2x^2+5x

Marat540 [252]2 years ago

3 0

Start off by distributing the x to x+2.
X^2+2x
X+x+3

ADD EVERYTHING TOGETHER
X^2+4x+3

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Solve the following linear equation for x x. 5 x − 2 + x = 9 + 3 x + 10 5x−2+x=9+3x+10

marta [7]

The answer is 6. Please mark BRAINLIEST!! :D

6 0

2 years ago

If 3x + 4y = 10 and 2x + 3y = 6, then x + y = ?

zavuch27 [327]

Answer:

x + y = 4

Step-by-step explanation:

Given the 2 equations

3x + 4y = 10 → (1)

2x + 3y = 6 → (2)

Subtract (2) from (1) term by term on both sides

x + y = 4

5 0

3 years ago

20 points!!

ANEK [815]

See below for the proof of the equation $\frac{ax + by}{x + y} - \frac{ax - by}{x - y}= 2(a - b)$

<h3>How to prove the equation?</h3>

The equation is given as:

$\frac{ax + by}{x + y} - \frac{ax - by}{x - y}= 2(a - b)$

Take the LCM

$\frac{(ax + by)(x - y) -(ax - by)(x + y)}{(x + y)(x - y)}= 2(a - b)$

Expand

$\frac{ax^2 - axy + bxy - by^2 -ax^2 - axy + bxy + by^2}{(x + y)(x - y)}= 2(a - b)$

Evaluate the like terms

$\frac{-2axy + 2bxy }{(x + y)(x - y)}= 2(a - b)$

Rewrite as:

$\frac{-2axy + 2bxy }{x^2 - y^2}= 2(a - b)$

Factorize the numerator

$\frac{2(a - b)(x^2 - y^2)}{x^2 - y^2}= 2(a - b)$

Divide

2(a - b)= 2(a - b)

Both sides are equal

Hence, the equation $\frac{ax + by}{x + y} - \frac{ax - by}{x - y}= 2(a - b)$ has been proved