All categories

2 years ago

Help i'll give brainliest help with number 13 and 14 please

Chemistry

1 answer:

Soloha48 [4]2 years ago

3 0

Answer:

ice:1

iceberg:2

water:3

lake:4

boiling water:5

Explanation:

You might be interested in

1. Mr. Brown weighs 670 newtons and he climbed a ladder that was 5 meters

ziro4ka [17]

Work = force*distance
Work = 670 * 5
Work = 3350 Nm

4 0

2 years ago

Write the balanced equation for a reaction between aqueous nitric acid (HNO3) and solid lithium metal (this is a single replacem

Lemur [1.5K]

Answer: The equation is given below.

Explanation:

Single replacement reactions are the chemical reactions in which more reactive metal displaces a less reactive metal from its chemical reaction. General equation for these reactions is given by the equation:

$A+BC\rightarrow AC+B$

Metal A is more reactive than metal B.

The reactivity of metals is judged with the help of reactivity series. In this series, the metals lying above are more reactive than the metals which lie below in the series.

For the reaction of solid lithium metal and nitric acid, the equation follows:

$3Li(s)+4HNO_3(aq.)\rightarrow 3LiNO_3(aq.)+2H_2O(l)+NO(g)$

This is a type of single replacement reaction because Lithium (more reactive metal) is replacing Hydrogen (less reactive metal) from the chemical reaction.

3 0

2 years ago

A 250.0-ml sample of ammonia, nh3 (g), exerts a pressure of 833 torr at 42.4 °c. what mass of ammonia is in the container

Lelu [443]

To solve this, let's assume ideal gas behavior.

PV=nRT
Let's solve for n. Convert units to SI units first.

Pressure = 833 torr(101325 Pa/760 torr) = 111,057.53 Pa
Volume = 250 mL(1 L/1000 mL)(1 m³/1000 L) = 2.5×10⁻⁴ m³
Temperature = 42.4 + 273 = 315.4 K

n = (8,314 J/mol·K)(315.4 K)/(111057.53 Pa)(2.5×10⁻⁴ m³)
n = 94.45 mol

The molar mass of ammonia is 17.031 g/mol.
Mass = 94.45*17.031 = 1,608.51 g ammonia

6 0

3 years ago

The molecule ethylbenzene is considered an....

noname [10]

D. Cycloalkene
________________________

5 0

2 years ago

How many moles of lithium hydroxide are required to react with 19.2 mol CO2, the average amount exhaled by a person each day?

sladkih [1.3K]

Answer:

38.4 mol LiOH

Explanation:

Step 1: Write the balanced neutralization equation

2 LiOH + CO₂ ⇒ Li₂CO₃ + H₂O

Step 2: Establish the appropriate molar ratio

According to the balanced equation, the molar ratio of LiOH to CO₂ is 2:1.

Step 3: Calculate how many moles of lithium hydroxide are required to react with 19.2 mol CO₂

19.2 mol CO₂ × 2 mol LiOH / 1 mol CO₂ = 38.4 mol LiOH

3 0

3 years ago