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Hitman42 [59]
3 years ago
5

Marcia flew her ultralight plane to a nearby town against a head wind of 15 km/h in 2h 20 min. the return trip under the same wi

nd conditions took 1h 24min. find the plane's air speed and the distance to the nearby town
Physics
2 answers:
insens350 [35]3 years ago
8 0

Let the distance between the towns be d and the speed of the air be s.

distance = speed * time

convert the minutes time into hours.

When flying into the wind, ground speed will be air speed MINUS wind speed, hence the against the wind trip is described by:

d

s−15

=

7

3

return trip is then :

d

s+15

=

7

5

Cross-multiplying both we get the two-variable system:

3d=7∗(s−15)5d=7∗(s+15)

3d=7s−1055d=7s+105

subtract first equation from second equation we get

2d=210d=105km

Substitute the value of d in the above equations for s.

5∗105=7s+1057s=420s=60km/hr

Oduvanchick [21]3 years ago
5 0
The answer to this question would be 60km per hour
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Answer:

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Explanation:

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As the object move from +2.79 x -coordinate to -5 x- coordinate

So total distance = 5+2.79 = 7.79 cm

Time is given as t = 2.55 sec

We have to find the acceleration

From second equation of motion we know that s=ut+\frac{1}{2}at^2

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3 years ago
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Firlakuza [10]

Answer:

e). The ratio is not given

Explanation:

<u>Capacitance of a capacitor</u>

The expression for the capacitance of a capacitor with di electric material is given as

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therefore the distance in A is 0.5mm

For the first (A) capacitor

C1=8εA/0.5

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For the Second (B) capacitor

C2=8εA/1

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8 0
3 years ago
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Explanation:

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