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CaHeK987 [17]
4 years ago
13

The force that slows down and eventually stops a ball you roll across the pavement is called

Physics
2 answers:
photoshop1234 [79]4 years ago
7 0
It’s called friction.
Irina-Kira [14]4 years ago
4 0
I would say friction is your answer!
You might be interested in
While skateboarding at 19 km/h throwning a tennis ball at 11 km/h what is the speed of the ball
Lina20 [59]

According to whom ?

So YOU're on your skateboard, and there's somebody else, sitting on HIS porch, watching you skate by on your board.

-- The man on the porch says you're skating by him at 19 km/hr .

-- You throw a tennis ball.  

. . . . . Do you throw it in the same direction that you're skateboarding, or do you throw it away behind you, toward the place you just came from ?

. . . . . Does it fly away from YOU at 11 km/hr ?  Or does it fly past the man on the porch at 11 km/hr ?

There are 4 possible combinations.  One of them is not possible.  Each of the other three combinations leads to two different answers to the question.  And ALL six answers are correct !

1).  You throw the ball forward, in the same direction you're skating.  It flies away from your hand at 11 km/hr.

To you, the speed of the ball is 11 km/hr, in the direction you're skating.  To the man on the porch, it's 30 km/hr, in the direction you're skating.

2). You throw the ball forward, in the same direction you're skating.  It flies past the porch at 11 km/hr.

This isn't possible.

3). You throw the ball backward, toward where you just came from.  It flies away from YOU at 11 km/hr.

To you, the speed of the ball is 11 km/hr, in the direction backward from you.  To the man on the porch, the speed of the ball is 10 km/hr in the direction you're skating.

4).  You throw the ball backward, toward where you just came from.  It flies past the porch at 11 km/hr.

To you, the speed of the ball is 8 km/hr, in the direction backward from you.  To the man on the porch, it's 11 km/hr in the direction you're skating.


NOW you're going to ask me "But what's the REAL speed of the ball ?"

The answer to THAT one is:  There's no such thing !  It all depends on WHO's measuring it ... where that observer is and how HE's moving.

The displacement, speed, velocity, acceleration, and energy of the ball, ALL depend on who's watching it and measuring it.

I'll be interested to see whether you mark this answer 'Brainliest', or report it because it's weird, confusing, and ridiculous.

3 0
4 years ago
a 300kg motorboat is turned off as it approaches a dock and coasts towards it at .5 m/s. Isaac, whose mass is 62 kg jumps off th
Zolol [24]

-- Before he jumps, the mass of (Isaac + boat) = (300 + 62) = 362 kg,
their speed toward the dock is 0.5 m/s, and their linear momentum is

  Momentum = (mass) x (speed) = (362kg x 0.5m/s) = <u>181 kg-m/s</u>

<u>relative to the dock</u>. So this is the frame in which we'll need to conserve
momentum after his dramatic leap.

After the jump:

-- Just as Isaac is coiling his muscles and psyching himself up for the jump,
he's still moving at 0.5 m/s toward the dock.  A split second later, he has left
the boat, and is flying through the air at a speed of 3 m/s relative to the boat.
That's 3.5 m/s relative to the dock.

    His momentum relative to the dock is (62 x 3.5) = 217 kg-m/s toward it.

But there was only 181 kg-m/s total momentum before the jump, and Isaac
took away 217 of it in the direction of the dock.  The boat must now provide
(217 - 181) = 36 kg-m/s of momentum in the opposite direction, in order to
keep the total momentum constant.

Without Isaac, the boat's mass is 300 kg, so 

                     (300 x speed) = 36 kg-m/s .

Divide each side by 300:  speed = 36/300 = <em>0.12 m/s ,</em> <u>away</u> from the dock.
=======================================

Another way to do it . . . maybe easier . . . in the frame of the boat.

In the frame of the boat, before the jump, Isaac is not moving, so
nobody and nothing has any momentum.  The total momentum of
the boat-centered frame is zero, which needs to be conserved.

Isaac jumps out at 3 m/s, giving himself (62 x 3) = 186 kg-m/s of
momentum in the direction <u>toward</u> the dock.

Since 186 kg-m/s in that direction suddenly appeared out of nowhere,
there must be 186 kg-m/s in the other direction too, in order to keep
the total momentum zero.

In the frame of measurements from the boat, the boat itself must start
moving in the direction opposite Isaac's jump, at just the right speed 
so that its momentum in that direction is 186 kg-m/s.
The mass of the boat is 300 kg so
                                                         (300 x speed) = 186

Divide each side by 300:  speed = 186/300 = <em>0.62 m/s</em>    <u>away</u> from the jump.

Is this the same answer as I got when I was in the frame of the dock ?
I'm glad you asked. It sure doesn't look like it.

The boat is moving 0.62 m/s away from the jump-off point, and away from
the dock.
To somebody standing on the dock, the whole boat, with its intrepid passenger
and its frame of reference, were initially moving toward the dock at 0.5 m/s.
Start moving backwards away from <u>that</u> at 0.62 m/s, and the person standing
on the dock sees you start to move away <u>from him</u> at 0.12 m/s, and <em><u>that's</u></em> the
same answer that I got earlier, in the frame of reference tied to the dock.

  yay !

By the way ... thanks for the 6 points.  The warm cloudy water
and crusty green bread are delicious.


4 0
3 years ago
For a freely falling object dropped from rest, what is the acceleration at the
Zinaida [17]

The acceleration of the object after 3 seconds of fall is -9.8 m/s².

The given parameters;

  • initial velocity of the object, u = 0
  • time of motion of the object, t = 3 seconds

Acceleration is the change in velocity per change in time of motion.

The acceleration of the object after 3 seconds of fall is calculated as follows;

  • Since the object is in free fall, the object experiences only acceleration due to gravity.
  • the magnitude of this acceleration due to gravity is 9.8 m/s²
  • the direction of this acceleration is downwards

 

Thus, the acceleration of the object after 3 seconds of fall is -9.8 m/s².

Learn more here: brainly.com/question/13197713

7 0
3 years ago
Question 3 of 5 What happens to the particles in a substance as it melts? O A. The particles slow down and become fixed in place
Mars2501 [29]

Answer:

D. The particles move more quickly and begin to move from place to place.

Explanation:

4 0
3 years ago
A car travels in a straight line with an average velocity of 80 km/h for 2.5 h and then with an average velocity of 40 km/h for
maks197457 [2]

Answer:

260 km

65 km/hr

Explanation:

The displacement of an object is the distance moved by that object in a particular direction.

velocity = displacement / time, therefore,

Displacement = velocity * time.

Total displacement for the 4 HR trip = displacement for 2.5 hr + displacement for 1.5 hr

total displacement = (80 * 2.5) + (40 * 1.5)

Total displacement = 200 + 60

Total displacement = 260 Km

average velocity for the total trip = total displacement / total time taken

average velocity = 260 km/ 4 hr

average velocity = 65 km/hr

7 0
4 years ago
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