1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
horsena [70]
3 years ago
9

Your friend has decided to make some money during the next State Fair by inventing a game of skill. In the game as she has devel

oped it so far, the customer shoots a rifle at a 5.0 cm diameter target falling straight down. Anyone who hits the target in the center wins a stuffed animal. Each shot would cost 50 cents. The rifle would be mounted on a pivot 1.0 meter above the ground so that it can point in any direction at any angle. When shooting, the customer stands 100 meters from where the target would hit the ground if the bullet misses. At the instant that the bullet is fired (with velocity of 1200 ft/sec according to the manual), the target is released from its holder 7.0 meters above the ground. (You see, the trigger is electronically connected to the release mechanism.) Your friend asks you to try out the game which she has set up on a farm outside of town. Before you fire the gun you calculate where you should aim. You may, as usual, neglect any effects of air resistance. Your conclusion? At what angle from the vertical should you aim?
Physics
1 answer:
coldgirl [10]3 years ago
4 0

Answer: from the vertical, one should aim  86.6°

Explanation:

height of the center of object = 7.0 m - 0.05 m = 6.95 m

now let the bullet hits centre at point A height x meters from the ground

also let t be the time taken for the bullet to hit the object

so distance travelled by the target will be

d = h - x = 6.95 - x

now using the equation of motion

d = 1/2gt²

so 1/2gt² = 6.95 - x

x = 6.95 - 1/2gt² .........let this be equ 1

let angle of fire be ∅

so v(cos∅) × t = 100

our velocity v is 1200 ft/sec = 365.76 m/s

365.76(cos∅) × t = 100 ........equ 2

also vertical position of the bullet after t is

y = y₀ + c(sin∅)t - 1/2gt²

y = 1 + 365.76(sin∅)t - 1/2gt² ----- equ 3

After time t. the vertical position x and y are same, else the bullet wouldn't have strike target at centre, so;

x = y

we substitute

equ 1 = equ 3

6.95 - 1/2gt² = 1 + 365.76(sin∅)t - 1/2gt²

6.95 - 1 = 365.76(sin∅)t - 1/2gt² +  1/2gt²

5.95 = 365.76(sin∅)t

t = 5.96 / 365.76(sin∅)

now input the above equ  into equ 2

365.76(cos∅) ×  5.96/365.76(sin∅) = 100

5.95(cos∅)/sin∅ = 100

tan∅ = 5.95/100 = 0.0595

∅ =  3.40°

therefore from the vertical, one should aim (90° - 3.40°) = 86.6°

You might be interested in
An echo is heard from a cliff 3.71 s after a rifle is fired. How many feet away is the cliff
LenKa [72]

The cliff is 2042 ft away.

We know that the speed of sound in air is directly proportional to the absolute temperature.

First convert the Fahrenheit temperature to Celsius;

 °C = 5/9(44.5 - 32)

°C = 6.9 °C

Applying the formula;

V1/V2 = √T1/T2

Where; V1 = velocity of sound in air at  0°C

V2 = Velocity of sound in air at 6.9 °C

1087/V2 = √273/279.9

V2= 1101 ft/s

Given that; V = 2s/t

Where s is the distance of the cliff

t is the time taken

1101 ft/s = 2s/3.71 s

s = 1101 ft/s × 3.71 s/2

s = 2042 ft

Learn more:brainly.com/question/15381147

3 0
3 years ago
BRAINLIEST PLZ HELP!
balu736 [363]
The correct answer should be A
5 0
3 years ago
If you are stopped, then get on a bike and accelerate 2 m/s/s south, what us your final velocity after 3 seconds? Please Explain
olga_2 [115]
Vf = Final velocity.
Vi = initial velocity
a = acceleration. 
t = time

Vf = Vi + at

Vf = 0 + (2 m/s^2)(3s)

Vf = 6 m/s south
4 0
3 years ago
What force is required to accelerate a 1,000 kg car 5 m/s2?
marysya [2.9K]
F = ma
F = (1000 kg)•(5 m/s^2)
F = 5000 N
5 0
3 years ago
Calculate the point of no return for an airport runway of 1.60 mi in length if a jet plane can accelerate at 10.1 ft/s2 and dece
Vilka [71]

Answer:

t = 26.39 s

Explanation:

given,

Length of runway = 1.60 mi = 8448 ft

acceleration of the jet = 10.1 ft/s²

deceleration of the jet = 7.21 ft/s²

Let x be the distance of no return

using equation of motion

v² = u² + 2 a s

v² = 0 + 2 × 10.1 × x

v = √(20.2 x)

now, after reaching that Point the deceleration of the plane start

using equation of motion

final velocity of the first case will be the initial velocity of the second case

v² = u² + 2 a s

0 = 20.2 x - 2 x 7.21 x(8448-x)

34.62 x = 121820.16

x = 3518.78 ft

time taken to reach no return point

x = ut+\dfrac{1}{2}at^2

3518.78 =\dfrac{1}{2}\times 10.1\times t^2

    t² = 696.788

    t = 26.39 s

time taken to reach the no return point is equal to 26.39 s.

8 0
3 years ago
Other questions:
  • What energy transformation takes place when you turn on a space heater?
    15·1 answer
  • What happens to a chemical reaction when the temperature is increased ?
    15·2 answers
  • Compare and contrast the inner and outer planets. (Must be in complete sentences) (At least 5 sentences).
    6·1 answer
  • In a Physics 111 laboratory experiment, a cart with a mass of 0.80 kg and a velocity of 0.50 m/s collides elastically into a sta
    8·1 answer
  • The instrument which is commonly used to measure the intensity of radioactivity is called a
    9·2 answers
  • What best describes the relationship between the frequency of an oscillation and the period of the oscillation?
    10·1 answer
  • Which statement best compares the momentum of a 5-kilogram fish swimming at a speed of 10 meters/second and a 2-kilogram fish sw
    5·2 answers
  • Help
    5·1 answer
  • Most ozone is found in a region of Earth’s
    7·1 answer
  • Joey is riding in an elevator which is accelerating upwards at 2.0 m/s2. The elevator weighs 300.0 kg, and Joey weighs 60.0 kg.
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!