Answer:
Incomplete question
This is the completed question
If the resistor in the circuit had a larger resistance then the current would be then have to be proportionally smaller. Because the batteries each give off 1.5 volts then the current would have to be the variable that would change. What affect would using a 12V car battery have on the operation of your circuit? (Do not try this.) What would happen to the current? What would happen to the resistor?
Explanation:
Using ohms law as our basis
Ohms law state that, the voltage in an ohmic conductor is directly proportional to the current
V∝I
Resistance is the constant of proportionality
Then
V=iR
Since we want a relationship between current and resistance.
then, I=V/R
So, current is inversely proportional to Resistance
as the current increase the resistance reduce and as the current reduces the resistance increases.
a. So, increasing the voltage from 1.5V to 12V increases the current In the circuit because voltage Is directly proportional to I.
From ohms law
V=iR
When v =1.5V
I=1.5/R
When V increase to 12V
I=12/R
I.e, it increases by a factor of 8. Eight times it's initial value
b. Now, the resistance in the circuit is the constant of proportionality and it doesn't change in a given circuit expect when using a variable resistoa r like rheostat.
Standard sea level pressure by definition equals 760 mm (29.92 inches) of mercury
Answer:
The actual work output is 1,125 kilojoules.
Explanation:
Energy efficiency is defined as the efficient use of energy. An appliance, process, or facility is energy efficient when it consumes less than the average amount of energy to perform an activity. Then, energy efficiency is the ratio between the amount of energy used in an activity and the amount expected to be carried out.
Efficiency is calculated as:
efficiency = output / input
Where output is the amount of mechanical work (in watts) or energy consumed by the process (in joules), and input (input) is the amount of work or energy that is used as input to carry out the process.
In this case:
- Efficiency always has a value between 0 and 1. In this case, efficiency=0.15
- output=?
- input= 7500 kilojoules
Replacing:
0.15=output/7500 kilojoules
Solving:
Output=0.15* 7500 kilojoules
output=1,125 kilojoules
<u><em>The actual work output is 1,125 kilojoules.</em></u>
The mover is pushing on the box, meaning that when hes pushing on the box hes adding force to the box to make it move. The box cant move without force.
Explanation:
We need to find the speed of a 3.1eV proton and a 3.1eV electron.
For proton, using conservation of energy such that,
is mass of proton
For electron,
is mass of proton
Hence, this is the required solution.
