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svetlana [45]
3 years ago
6

A 0.5 kg ball moving at a speed of 3m/s rolls up a hill. How high does the ball roll before it stops

Physics
1 answer:
andreyandreev [35.5K]3 years ago
3 0
According to conservation of energy
Kinetic energy at the bottom of hill = potential energy at top of hill
Kinetic energy(KE)= 0.5×mass(m)×velocity(v)²
where m=0.5 kg, and v= 3 m/s, v²=9 
KE=0.5×0.5×9=2.25 J = PE
PE=m×gravitational acceleration(g)×height(h)
h=2.25/(0.5×9.8)=0.459 m
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Answer:

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Explanation:

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velocity of the bullet(v)  = 750 m/s

a) momentum of bullet = m × v

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b) recoil velocity                                                      

m × u + M × U = m × v + M × V

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3 years ago
A person notices a mild shock if the current along a path through the thumb and index finger exceeds 82 µA. Find the maximum all
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Answer:

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Answer:

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