Solution :
Given :
M = 0.35 kg
Total mechanical energy = constant
or 
But 
and 
Therefore, potential energy at the top = kinetic energy at the bottom
(h = 35 cm = 0.35 m)
= 2.62 m/s
It is the velocity of M just before collision of 'm' at the bottom.
We know that in elastic collision velocity after collision is given by :
here, 
∴ 
= 0.33 m/s
Therefore, velocity after the collision of mass M = 0.33 m/s
Answer:
The heat transferred into the system is 183.5 J.
Explanation:
The first law of thermodynamics relates the heat transfer into or out of a system to the change of internal and the work done on the system, through the following equations.
ΔU = Q - W
where;
ΔU is the change in internal energy
Q is the heat transfer into the system
W is the work done by the system
Given;
ΔU = 155 J
W = 28.5 J
Q = ?
155 = Q - 28.5
Q = 155 + 28.5
Q = 183.5 J
Therefore, the heat transferred into the system is 183.5 J.
the acceleration or the next force acting on the body is constant
