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Gnesinka [82]
3 years ago
6

Phosphorus (P) is a nonmetal, which is a poor conductor of heat and electricity. Which of the elements listed below shares these

properties?
Group of answer choices

strontium (Sr)

sodium (Na)

iodine (I)

calcium (Ca)
Chemistry
1 answer:
tankabanditka [31]3 years ago
8 0

Answer:

Sodium is the answer

Explanation:

You might be interested in
TRIPLE POINTS!!! I NEED HELP!!! PLEASE EXPLAIN TOO!!! What is the energy of a quantum of light with a frequency of 4.31 x 1014 1
Lelechka [254]

Answer:

The answer is

2.86 \times  {10}^{ - 19}  \: J

Explanation:

The energy of a quantum of light can be found by using the formula

<h3>E = hf</h3>

where

E is the energy

f is the frequency

h is the Planck's constant which is

6.626 × 10-³⁴ Js

From the question

f = 4.31 × 10¹⁴ Hz

We have

E = 4.31 × 10¹⁴ × 6.626 × 10-³⁴

We have the final answer as

2.86 \times  {10}^{ - 19}  \: J

Hope this helps you

3 0
3 years ago
At equilibrium, no chemical reactions take place. true or false
arsen [322]
False. At equilibrium, the rate of forward reaction is equal to the rate of backward reaction. The net concentration of both products and reactants won't change, but the reactions still take place.
6 0
3 years ago
If a penny (with the this volume .39 cm^3) was made out of pure copper, what should its mass be?
blondinia [14]

Answer:

  3.49 g

Explanation:

The mass is the product of volume and density:

  (8.96 g/cm³)(0.39 cm³) ≈ 3.49 g

The mass of a pure-copper penny would be 3.49 g.

5 0
3 years ago
How many moles of iron (iii) oxide are in a 120 gram sample of fe2o3?
AnnyKZ [126]
First find the molar mass of Fe2O3, after you would want to do this
120 g Fe2O3 x 1 mol = # mol
Molar Mass
3 0
3 years ago
Start with 100.00 mL of 0.10 M acetic acid, CH3COOH. The solution has a pH of 2.87 at 25 oC. a) Calculate the Ka of acetic acid
jasenka [17]

Answer: a) The K_a of acetic acid at 25^0C is 1.82\times 10^{-5}

b) The percent dissociation for the solution is 4.27\times 10^{-3}

Explanation:

CH_3COOH\rightarrow CH_3COO^-H^+

 cM              0             0

c-c\alpha        c\alpha          c\alpha

So dissociation constant will be:

K_a=\frac{(c\alpha)^{2}}{c-c\alpha}

Give c= 0.10 M and \alpha = ?

Also pH=-log[H^+]

2.87=-log[H^+]  

[H^+]=1.35\times 10^{-3}M

[CH_3COO^-]=1.35\times 10^{-3}M

[CH_3COOH]=(0.10M-1.35\times 10^{-3}=0.09806M

Putting in the values we get:

K_a=\frac{(1.35\times 10^{-3})^2}{(0.09806)}

K_a=1.82\times 10^{-5}

b)  \alpha=\sqrt\frac{K_a}{c}

\alpha=\sqrt\frac{1.82\times 10^{-5}}{0.10}

\alpha=4.27\times 10^{-5}

\% \alpha=4.27\times 10^{-5}\times 100=4.27\times 10^{-3}

5 0
3 years ago
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