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makkiz [27]
3 years ago
7

What happens with the atomic numbers in nuclear equations?

Chemistry
1 answer:
MatroZZZ [7]3 years ago
7 0

Answer:

increase

Explanation:

more

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Convert the volume 0.455 m3 to the unit mL
Stells [14]
The answer is 455000
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4 years ago
How to add magnisume and chloride togather
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Magnesium plus chlorine equals to magnesium chloride
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3 years ago
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Synthesis gas consists of a mixture of H2 and CO. Calculate at 101kpa is compressed at constant temperature from 7.20 dm3 to 4.2
bazaltina [42]

Answer:

The final pressure is 173 kPa.

Explanation:

A mixture of gases at an initial pressure of  P₁ = 101 kPa is compressed from an initial volume V₁ = 7.20 dm³ to a final volume V₂ = 4.21 dm³. If we suppose an ideal gas behavior and that temperature remains constant, we can apply Boyle's law to find out the final pressure P₂:

P₁ . V₁ = P₂ . V₂

P_{2}=\frac{P_{1}.V_{1}}{V_{2}}=\frac{101kPa.7.20dm^{3} }{4.21dm^{3} }  =173kPa

5 0
4 years ago
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When you standardized the Na2S2O3, what molarity of Na2S2O3 did you obtain?
nikdorinn [45]

Answer:

0.46M NaS₂O₃ (Assuming KIO₃ solution with a concentration of 1.0M)

Explanation:

Based on the reaction:

6 Na₂S₂O₃ + KIO₃ + 5 KI + 3 H₂SO₄ → 3 Na₂S₄O₆ + 3 H₂O + 3 K₂SO₄ + 6 NaI

<em>6 moles of  Na₂S₂O₃ react per mole of KIO₃</em>

Assuming the molarity of the KIO₃ solution is 0,1M:

Moles of KIO₃: = 5.0x10⁻³L ₓ (0.1 mol / L) = <em>5.0x10⁻⁴ moles</em>

As 6 moles of thiosulfate reacted per mole of iodate:

5.0x10⁻⁴ moles KIO₃ ₓ (6 moles Na₂S₂O₃ /  1 mole KIO₃) =

<em>3.0x10⁻³ moles of Na₂S₂O₃. </em>In 6.5mL (6.5x10⁻³L):

3.0x10⁻³moles Na₂S₂O₃ / 6.5x10⁻³ L = 0.46M NaS₂O₃

6 0
3 years ago
A 2.10g of unknown monoprotic acid is titrated with 38.10 mL of .265M NaOH. Calculate the molar mass of the ac? I already calcul
Shkiper50 [21]
V_{NaOH}=38,1mL=0,0381L\\&#10;C_{m}=0,265M\\\\&#10;n=C_{m}*V=0,265\frac{mol}{L}*0,0381L\approx0,0101mol

HR    +      NaOH ⇒ NaR + H₂O
1mol   :     1mol

0,0101mol \ \ \ \ \Rightarrow \ \ \  \ 2,1g\\&#10;1mol  \ \ \ \ \ \ \ \ \ \ \Rightarrow \ \ \ m\\\\&#10;m=\frac{1mol*2,1g}{0,0101mol}\approx 207,92g\\\\&#10;M_{HR}=207,92\frac{g}{mol}
5 0
3 years ago
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