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3 years ago

On the pH scale pure water has a pH of A. 0 B. 7 C. 14

Chemistry

2 answers:

konstantin123 [22]3 years ago

7 0

Answer:its b 7

Explanation:

7 is neutral and pure water is the middle man

icang [17]3 years ago

5 0

Answer:

Explanation:B is correct because even in pure water ions tend to form due to random processes( producing some H+ and OH- ions).

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When the ph of an aqueous solution is changed from 1 to 2, the concentration of hydronium ions in the solution is.

kiruha [24]

Answer:

decreased by a factor of 10

Explanation:

pH is defined in such a way that;

pH= −log10(H)

Where H represents the concentration of Hydronium or Hydrogen ions

Given that pH is changed from 1 to 2,

By rearranging the above formula , we get 10−pH = H

if pH=1,H=10−1=0.1M
if pH=2,H=10−2=0.01M

Therefore, 0.1/0.01 = 10 and 0.1 > 0.01

Hence, the concentration of hydronium ions in the solution is decreased by a factor of 10

7 0

2 years ago

6. A. If 4.50 mols of ethane, C2H6, undergoes combustion according to the unbalanced equation

uranmaximum [27]

Answer:

for one mole of C2H6 there are 7/2 mole of O2 required. so for4. 50 moles you require 4.50 x 7/2 = 15.75 moles of O2.

Explanation:

i hope it's helpful

6 0

3 years ago

One of a frogs biggest defense is a. Eyesight b. Camoflauge c. Ability to swim

Serhud [2]

Answer:

Your answer has to be B. Camouflage

Explanation:

3 0

3 years ago

A 1,350-Kg car travels at 12 <br> M/s. What is its kinetic energy??

polet [3.4K]

Answer:

The kinetic energy of the car will be 97.2.

8 0

3 years ago

A chamber with a fixed volume is shown above. The temperature of the gas inside the chamber before heating is 25.2 C and it’s pr

rusak2 [61]

Answer:

Explanation:

Given parameters:

Initial temperature T₁ = 25.2°C = 25.2 + 273 = 298.2K

Initial pressure = P₁ = 0.6atm

Final temperature = 72.4°C = 72.4 + 273 = 345.4K

Unknown:

Final pressure = ?

Solution:

To solve this problem, we use an adaption of the combined gas law where the volume gas is fixed. This simplification results into:

$\frac{P_{1} }{T_{1} } = \frac{P_{2} }{T_{2} }$

where P and T are temperatures, 1 and 2 are initial and final temperatures.

Input the parameters and solve;

$\frac{0.6}{298.2} = \frac{P_{2} }{345.4}$

P₂ = 0.7atm

3 0

3 years ago