Answer:
125/6(In(x-25)) - 5/6(In(x+5))+C
Step-by-step explanation:
∫x2/x1−20x2−125dx
Should be
∫x²/(x²−20x−125)dx
First of all let's factorize the denominator.
x²−20x−125= x²+5x-25x-125
x²−20x−125= x(x+5) -25(x+5)
x²−20x−125= (x-25)(x+5)
∫x²/(x²−20x−125)dx= ∫x²/((x-25)(x+5))dx
x²/(x²−20x−125) =x²/((x-25)(x+5))
x²/((x-25)(x+5))= a/(x-25) +b/(x+5)
x²/= a(x+5) + b(x-25)
Let x=25
625 = a30
a= 625/30
a= 125/6
Let x= -5
25 = -30b
b= 25/-30
b= -5/6
x²/((x-25)(x+5))= 125/6(x-25) -5/6(x+5)
∫x²/(x²−20x−125)dx
=∫125/6(x-25) -∫5/6(x+5) Dx
= 125/6(In(x-25)) - 5/6(In(x+5))+C
Answer:
x=12.6
Step-by-step explanation:
5x -9 / 7
5x= -9x7
5x= -63
x= -63/5 = -12.6
x= -12.6
a = length of one side.
Area of a square = a^2
in our problem,
Area = 169 square inches
a = ?
Plug our numbers into the area formula mentioned above.
169 in^2 = a^2.
Take the square root of each side to find the side length of the square shaped platter.
13 = a
Answer:
85.1 ft
Step-by-step explanation:
The extreme water slide forms a 20 angle with the tower it leans against 80 feet above the ground find the length of the slide x
We solve using the Trigonometric function of Cosine
cos y = adjacent/hypotenuse
y = angle = 20°
Adjacent = 80 ft
Hypotenuse = ?
cos 20 = 80/Hypotenuse
Hypotenuse = 80/cos 20
x = 85.134221798 ft
Approximately = 85.1 ft
Length of the slide = 85.1 ft