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irina1246 [14]
3 years ago
13

How many neutrons does Aluminum - 28 have?

Chemistry
2 answers:
scoundrel [369]3 years ago
8 0

Answer: 14 neutrons

Explanation:

lions [1.4K]3 years ago
7 0

the 28 represents the mass number of Aluminum. And Naturally, aluminum has 13 protons (Atomic number)

so to find the number of Neutrons in aluminum, use this relation

Neutron number = mass number - proton or atomic number

substitute the values into it

neutron number = 28-13

neutron number = 15

<em>ther</em><em>efore</em><em> </em><em>,</em><em>ther</em><em>e</em><em> </em><em>are</em><em> </em><em>1</em><em>5</em><em> </em><em>neutr</em><em>ons</em><em> </em><em>in</em><em> </em><em>the</em><em> </em><em>alumi</em><em>num</em><em> </em><em>atom</em><em>.</em>

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F a sample of butene (C4H8) that has a mass of 136.6 g is combusted in excess oxygen, what is the mass of CO2 that is produced?
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3 years ago
How does a molecule differ from an atom?
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If 20.0 g of NaOH is added to 0.750 L of 1.00 M Cd(NO₃)₂, how many grams of Cd(OH)₂ will be formed in the following precipitatio
bulgar [2K]

Answer:

m_{Cd(OH)_2}=36.6 gCd(OH)_2

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Hello.

In this case, for the given chemical reaction, in order to compute the grams of cadmium hydroxide that would be yielded, we must first identify the limiting reactant by computing the yielded moles of that same product, by 20.0 grams of NaOH (molar mass = 40 g/mol) and by 0.750 L of the 1.00-M solution of cadmium nitrate as shown below considering the 1:2:1 mole ratios respectively:

n_{Cd(OH)_2}^{by\ NaOH}=20.0gNaOH*\frac{1molNaOH}{40gNaOH} *\frac{1molCd(OH)_2}{2molNaOH} =0.25molCd(OH)_2\\\\n_{Cd(OH)_2}^{by\ Cd(NO_3)_2}=0.750L*1.00\frac{molCd(NO_3)_2}{L}*\frac{1molCd(OH)_2}{1molCd(NO_3)_2}  =0.75molCd(OH)_2

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m_{Cd(OH)_2}=0.25molCd(OH)_2*\frac{146.4gCd(OH)_2}{1molCd(OH)_2} \\\\m_{Cd(OH)_2}=36.6 gCd(OH)_2

Best regards.

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2 years ago
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