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irina1246 [14]
3 years ago
13

How many neutrons does Aluminum - 28 have?

Chemistry
2 answers:
scoundrel [369]3 years ago
8 0

Answer: 14 neutrons

Explanation:

lions [1.4K]3 years ago
7 0

the 28 represents the mass number of Aluminum. And Naturally, aluminum has 13 protons (Atomic number)

so to find the number of Neutrons in aluminum, use this relation

Neutron number = mass number - proton or atomic number

substitute the values into it

neutron number = 28-13

neutron number = 15

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How many moles of O2 are needed to burn 2.56 moles of CH3OH?
lukranit [14]

Answer:

n_{O_2}=3.84molO_2

Explanation:

Hello!

In this case, since the combustion reaction of methanol is:

CH_3OH+\frac{3}{2} O_2\rightarrow CO_2+2H_2O

In such a way, since there is 1:3/2 mole ratio between methanol and oxygen, we can compute the moles of oxygen that are needed to burn 2.56 moles of methanol as shown below:

n_{O_2}=2.56molCH_3OH*\frac{\frac{3}{2}molO_2}{1molCH_3OH} \\\\n_{O_2}=3.84molO_2

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6 0
3 years ago
Soil particles tend to be __________ charged and attract __________ charged ions.
aliina [53]

Answer:it’s abc it’s just science you know

Explanation:

8 0
3 years ago
4. Consider the following half-reactions: MnO4–(aq) + 8H+(aq) + 5e– → Mn+2(aq) + 4H2O(l) NO3–(aq) + 4H+(aq) + 3e– → NO(g) + 2H2O
jeyben [28]

Explanation:

The chemical reaction given in the question is as follows -

MnO₄⁻ (aq) + 8H⁺ (aq) + 5e⁻ → Mn²⁺ (aq) + 4H₂O (l)

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As we know , the value for reduction potential are -

Mn²⁺ = + 1.51  V

NO₃⁻  =  +0.96 V

From , the data given above , the value of the reduction potential of NO₃⁻ is less than the reduction potential of Mn²⁺ .

Hence ,

NO₃⁻  can not oxidize Mn²⁺ .

5 0
3 years ago
Upon arrival we needed to hunt in this new land we only had five refills and they needed 50 g of gunpowder to be shot once. We o
emmasim [6.3K]

Answer:

Explanation:

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The limiting reagent is the number of refills, and withonly 5, we are out of luck and can't kill one turkey

6 0
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