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sineoko [7]
3 years ago
15

A compound, like water, can be broken down (decomposed) by:

Chemistry
2 answers:
Sever21 [200]3 years ago
7 0

Answer:

electrolysis is the correct answer.

Explanation:

Water is decomposed into hydrogen and oxygen gases using electricity. A Hoffman electrolysis apparatus collects the two gases separately and shows the 2 to 1 ratio nicely. ... Hoffman electrolysis apparatus. 2 electrodes - one is nichrome wire and the other is platinum wire and foil.

Go look up Hoffman apparatus.

Ivanshal [37]3 years ago
6 0
<h3>Answer:</h3>

Electrolysis

<h3>Explanation:</h3>
  • Electrolysis refers to the process of decomposing an electrolyte by passing an electric current through it.
  • Electrolytes are ionic compounds either in molten or aqueous form that may be decomposed by passing an electric current through them.
  • Water is an example of an electrolyte that can be decomposed using electrolysis.
  • During electrolysis cations undergo reduction at the cathode while anions undergo oxidation at the anode.

In this case;

At the Cathode;

4H⁺(aq) + 4e → 2H₂(g)

At the Anode;

4OH⁻(aq) → H₂O(l) + O₂(g) + 4e

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Calculate ΔH∘f for NO(g) at 435 K, assuming that the heat capacities of reactants and products are constant over the temperature
weeeeeb [17]

Answer:

91383 J

Explanation:

The equation of the reaction can be represented as:

\frac{1}{2} N_{2(g)}+\frac{1}{2} O_{2(g)}     ------>NO_{(g)}

Given that:

The standard enthalpy of formation of NO(g) is 91.3 kJ⋅mol−1 at 298.15 K.

The equation below shown the reaction between the enthalpy of reaction at a particular temperature to another.

\delta H^0__{R,T_2} = \delta H^0__{R,T_1} } + \int\limits^{T_2}_{T_1} {\delta C_p(T')} \, dT'

where:

\delta H^0__{R} = enthalpy of reaction

{\delta C_p(T')} = the difference in the heat capacities of the products and the reactants.

∴

\delta H^0__{R,435K} = \delta H^0__{R,298.15K} + \int\limits^{435}_{298.15} {\delta C_p(T')} \, dT'

= 1(91300 J.mol^{-1} ) +\int\limits^{435}_{298.15} [{(29.86)-\frac{1}{2}(29.38)-\frac{1}{2}29.13}]J.K^{-1}.mol^{-1} \, dT'

= 91300 J + (0.605 J.K⁻¹)(435-298.15)K

= 91382.79 J

\delta H^0__{R,435K} ≅ 91383 J

6 0
3 years ago
suppose medical records indicate that the length of newborn babies (in inches) is normally distributed with a mean of 20 and a s
Tanya [424]

Answer:

  • <u>0.6826 (68.26%)</u>

Explanation:

<u>1) Find the z-scores:</u>

  • z = [X - μ ] / σ

a) z-score for 22.6 inches length

  • X = 22.6
  • μ = 20
  • σ = 2.6

  • z = [ 22.6 - 20 ] / 2.6 = 1.00

b) z-score for 17.4 inches length

  • X = 17.4
  • μ = 20
  • σ = 2.6

  • z = [ 17.4 - 20 ] / 2.6 =  - 1.00

<u>2) Probability</u>

Then, you have to find the probability that the length of an infant is between - 1.00 and 1.00 standards deviations (σ) from the mean (μ).

That is a well known value of 68%, which is part of the 68-95-99.7 empirical rule.

The most exact result is obtained from tables and is 68.26%:

  • 1 - P (z ≥ 1.00) - P (z ≤ - 1.00) = 1 - 0.1587 - 0.1587 = 0.6826 = 68.26%
5 0
3 years ago
How does the law of conservation of mass apply to this reaction C2H4+4O2--&gt;4H2O+2CO2 .Only the oxygen needs to be balanced B.
r-ruslan [8.4K]
C2H4+4O2-->4H2O+2CO2

the answer is C
6 0
3 years ago
Read 2 more answers
Determine if the bond between each pair of atoms is pure covalent, polar covalent, or ionic. drag the appropriate items to their
dsp73

Types of Bonds can be predicted by calculating the difference in electronegativity.

If, Electronegativity difference is,

 

                Less than 0.4 then it is Non Polar Pure Covalent

                

                Between 0.4 and 1.7 then it is Polar Covalent 

            

                Greater than 1.7 then it is Ionic

 

For Br and Br,

                    E.N of Bromine      =   2.96

                    E.N of Bromine      =   2.96

                                                   ________

                    E.N Difference             0.00         (Non Polar/Pure Covalent)

 

For N and O,

                    E.N of Oxygen      =   3.44

                    E.N of Nitrogen     =   3.04

                                                   ________

                    E.N Difference             0.40           (Non Polar/Pure Covalent)

 

For P and H,

                    E.N of Hydrogen       =   2.20

                    E.N of Phosphorous  =   2.19

                                                              ________

                    E.N Difference                  0.01          (Non Polar/Pure Covalent)

 

For K and O,

                    E.N of Oxygen          =   3.44

                    E.N of Potassium      =   0.82

                                                   ________

                    E.N Difference                2.62              (Ionic)

6 0
3 years ago
To study earths interior, geologist often rely on indirect methods, such as evidence from fossils.
igomit [66]

Answer: false

Explanation:

It is false that to study Earth's interior, geologists often rely on indirect methods, such as evidence from fossils. They rely on seismic wave.

6 0
3 years ago
Read 2 more answers
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