1.38 moles of oxygen
Explanation:
Thermal decomposition of Lead (II) nitrate is shown by the balanced equation below;
2Pb(NO₃)₂ → 2PbO + 4NO₂ + O₂
The mole ration of Lead (II) nitrate to oxygen is 2: 1
Therefore 2.76 moles of Lead (II) nitrate will lead to production of? moles of oxygen;
2: 1
2.76: x
Cross-multiply;
2x = 2.76 * 1
x = 2.76 / 2
x = 1.38
B it is a molecule. Not really much to explain about it.
<u>Answer:</u> The net chemical equation is given below.
<u>Explanation:</u>
To determine the net chemical equation, we will look into the intermediate steps:
<u>Step 1:</u> Formation of ammonia from hydrogen and nitrogen gas.
......(1)
<u>Step 2:</u> Formation of nitric acid from ammonia and oxygen gas.
.....(2)
The net chemical equation for the formation of nitric acid from hydrogen gas, nitrogen gas and oxygen gas follows by adding both the equations, we get:
By Stoichiometry of the reaction:
1 mole of hydrogen gas reacts with 2 moles of oxygen gas and 3 moles of hydrogen gas to produce 1 mole of nitric acid, 1 mole of water and 1 mole of ammonia.
Hence, the net chemical equation is given below.
Answer:
Explanation:
Hello!
In this case, since we volume, pressure and temperature which are all changing, we can use the combined ideal gas law to write:
Thus, since the final volume V2 is required, by solving for it, we write:
In such a way, we plug in the given data to obtain:
Which means that the process compressed the gas.
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