the system is in constant temperature
so it follows Boyle's law
i.e.P1V1=P2P2
where P1=initial pressure=788 tour
P2=final pressure= ?
V1=initial volume=235 ml
V2=final volume=0.115 ml
Answer:
First option:
[NH3]2 / [N2][H2]3
Explanation:
First of all we need to determine the reaction:
N₂(g) + 3H₂(g) → 2NH₃(g)
1 mol of nitrogen can combine with 3 moles of hydrogen to produce 2 moles of ammonia.
Remember that Kc has to involve Molar concentrations of products / reactants
Concentration must be elevated to the stoichiometry coefficient
Kc for the reaction is: [NH₃]² / [N₂] . [H₂]³
Remember the vital equations for this:
(freezing point depression) = (Depression Constant) * (molality of solution)
Molality = (moles of solute) / (kg of solvent)
Step 1: Find molar mass of glucose
6 carbon * (12.01 g/mol) + 12 hydrogen * (1.01 g/mol) + 6 oxygen (16.00 g/mol)
= 180.18 g/mol
21.5 g glucose * (1 mole glucose / 180.18 g glucose) = 0.119 moles of glucose
Step 2: Convert grams of solvent to kilograms of solvent
255 g H2O * (1 kg/1000g) = 0.255 kg H2O
Step 3: Find the molality of the solution
molality = (moles solute)/(kg solvent)
molality = (0.119 moles glucose)/(0.255 kg H2O solvent) = 0.468 m (molal)
Step 4: Plug into depression equation
FP-depression = (-1.86°C/m) * (0.468 m) = -0.870 <span>°C</span>
Answer:
.001 ? Try a notation calculator
Answer: 1.15L
Explanation:Please see attachment for explanation
