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zaharov [31]
3 years ago
5

A chemist needs 1.36 mol of strontium bromide, SrBr2, for a reaction. What mass of strontium chloride should the chemist use?

Chemistry
2 answers:
yaroslaw [1]3 years ago
5 0
Mass SrBr2 = 247.42 g/mol x 1.36 mol 
<span>= 336 g</span>
a_sh-v [17]3 years ago
4 0

Answer: 336.5 grams

Explanation:

According to avogadro's law, 1 mole of every substance weighs equal to the molecular mass and contains avogadro's number 6.023\times 10^{23} of particles.

convert given masses into moles.

Number of Moles =\frac{\text{ given mass}}{\text{ molar mass}}

Given number of moles = 1.36

Molar mass of SrBr_2 = 247.43 g/mol

Putting in the values we get

1.36=\frac{\text {given mass}}{247.43g/mole}

{\text {given mass}}=336.5grams

Thus mass of strontium bromide used should be 336.5 grams.

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Atomic mass = Number of protons + number of neutrons

Hope this helps!
3 0
3 years ago
Based on the equations below, which metal is the least active? Pb(NO3)2(aq) + Ni (s) --&gt; Ni(NO3)2 (aq)+ Pb(s) Pb(NO3)2(aq) +
viva [34]

Answer:

Ni

Explanation:

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Active metals react with other metals that are lower than them in the activity thereby displacing the lower metals from a solution of their salts. This is what may have happened in the other two reactions.

Ni is the most active metal listed in the question since it can react a compounds with Pb(NO3)2(aq) to liberate Pb metal.

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2 years ago
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For the reaction, identify the Lewis acid and the Lewis base.<br> AlF3 + CH3F → CH3+ + [AlF4]-
Ivanshal [37]
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In Given Reaction,
<span>                               AlF</span>₃<span> + CH</span>₃<span>F → CH</span>₃⁺<span> + [AlF</span>₄<span>]</span>⁻

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3 0
3 years ago
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