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rosijanka [135]
2 years ago
11

What's the pH of a solution composed of 0.2 moles of NH3 and 0.15 moles of nh4cl​

Chemistry
1 answer:
Norma-Jean [14]2 years ago
8 0

Answer:

pH=4.63

Explanation:

Hello!

In this case, since the ionization of ammonia, which is a weak base, is written as:

NH_3+H_2O\rightleftharpoons NH_4^++OH^-

We can see that the ammonium ion is the conjugate acid whereas the hydroxide ions the conjugate base; that is why we use the Henderson-Hasselbach equation to compute the pH, given the pKb of ammonia 4.75:

pH=pKb+log(\frac{[conj\ acid]}{[base]} )

In such a way, for the given moles of ammonia, base, and those of ammonium chloride, conjugate acid form, we obtain:

pH=4.75+log(\frac{0.15}{0.2} )\\\\pH=4.63

Best regards!

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In another experiment, if 80 xo3 molecules react with 104 brz3 molecules how many br2 molecules will be produced which reactant
BaLLatris [955]

This is an incomplete question, here is a complete question.

The balanced chemical reaction is:

6XO_3+8BrZ_3\rightarrow 6XZ_4+4Br_2+9O_2

In another experiment, if 80 XO_3 molecules react with 104 BrZ_3 molecules. How many Br_2 molecules will be produced which reactant will be used up in the reaction.

Answer : The number of molecules of Br_2  will be, 52 molecules and BrZ_3 reactant will be used up in the reaction because it is a limiting reagent and it limits the formation of product.

Explanation :

The balanced chemical reaction is:

6XO_3+8BrZ_3\rightarrow 6XZ_4+4Br_2+9O_2

First we have to determine the limiting reagent.

From the balanced reaction we conclude that,

As, 8 molecules of BrZ_3 react with 6 molecule of XO_3

So, 104 molecules of BrZ_3 react with \frac{104}{8}\times 6=78 molecule of XO_3

From this we conclude that, XO_3 is an excess reagent because the given moles are greater than the required moles and BrZ_3 is a limiting reagent and it limits the formation of product.

Now we have to calculate the molecules of Br_2

From the reaction, we conclude that

As, 8 molecules of BrZ_3 react to give 4 molecules of Br_2

So, 104 molecules of BrZ_3 react to give \frac{104}{8}\times 4=52 molecules of Br_2

Hence, the number of molecules of Br_2  will be, 52 molecules and BrZ_3 reactant will be used up in the reaction because it is a limiting reagent and it limits the formation of product.

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Explanation:

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the reaction will come to a halt and the other reactant will still be present.

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What is the molality of a solution when 0.50 moles glucose is dissolved in 750 g of water?
xxMikexx [17]

Answer:

0.67mol/Kg

Explanation:

The following were obtained from the question:

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