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rosijanka [135]
3 years ago
11

What's the pH of a solution composed of 0.2 moles of NH3 and 0.15 moles of nh4cl​

Chemistry
1 answer:
Norma-Jean [14]3 years ago
8 0

Answer:

pH=4.63

Explanation:

Hello!

In this case, since the ionization of ammonia, which is a weak base, is written as:

NH_3+H_2O\rightleftharpoons NH_4^++OH^-

We can see that the ammonium ion is the conjugate acid whereas the hydroxide ions the conjugate base; that is why we use the Henderson-Hasselbach equation to compute the pH, given the pKb of ammonia 4.75:

pH=pKb+log(\frac{[conj\ acid]}{[base]} )

In such a way, for the given moles of ammonia, base, and those of ammonium chloride, conjugate acid form, we obtain:

pH=4.75+log(\frac{0.15}{0.2} )\\\\pH=4.63

Best regards!

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a 3.81 g sample of NaHCO3 was completely decomposed. After decomposition, Na2CO3 had mass of 2.86g. Determine mass of H2CO3 prod
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Answer:

1.67g H2CO3 are produced

Explanation:

Based on the reaction:

2NaHCO3 → Na2CO3 + H2CO3

<em>2 moles of NaHCO3 produce 1 mole of Na2CO3 and 1 mole of H2CO3</em>

To solve this question we need to find the moles of Na2CO3 = Moles of H2CO3. With their moles we can find the mass of H2CO3 as follows:

<em>Moles Na2CO3 -Molar mass: 105.99g/mol-</em>

2.86g Na2CO3 * (1mol/105.99g) = 0.02698 moles Na2CO3 = Moles H2CO3

<em>Mass H2CO3 -Molar mass: 62.03g/mol-</em>

0.02698 moles  * (62.03g/mol) =

<h3>1.67g H2CO3 are produced</h3>

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