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rosijanka [135]
3 years ago
11

What's the pH of a solution composed of 0.2 moles of NH3 and 0.15 moles of nh4cl​

Chemistry
1 answer:
Norma-Jean [14]3 years ago
8 0

Answer:

pH=4.63

Explanation:

Hello!

In this case, since the ionization of ammonia, which is a weak base, is written as:

NH_3+H_2O\rightleftharpoons NH_4^++OH^-

We can see that the ammonium ion is the conjugate acid whereas the hydroxide ions the conjugate base; that is why we use the Henderson-Hasselbach equation to compute the pH, given the pKb of ammonia 4.75:

pH=pKb+log(\frac{[conj\ acid]}{[base]} )

In such a way, for the given moles of ammonia, base, and those of ammonium chloride, conjugate acid form, we obtain:

pH=4.75+log(\frac{0.15}{0.2} )\\\\pH=4.63

Best regards!

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poizon [28]
We know that each millimeter contains 10⁻³ meters. Writing this as a ratio:
1 mm : 10⁻³ m

We require a conversion from m³ to mm³, so we must take the cube of the ratio we have made:
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Therefore, the conversion used will be:
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7 0
3 years ago
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vova2212 [387]

Answer:

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Explanation:

Enthalpy of formation is the heat change when one mole of a substance is formed from its element in its standard states and in standard conditions of temperature and pressure. it may be positive or negative, if positive, it is an endothermic reaction where the heat content of the product is greater than that of the reactants, and if negative, it is exothermic reaction - where the heat content of the reactants is greater than the products. the enthalpy of formation is measured in KiloJoule/Moles (KJ/Mole).

From the value of the enthalpy of formation of NaHCO3, it shows that the reaction is exothermic, that is the formation of NaHCO3 from its constituents elements. As such, the heat content of the reactants is greater than the products.

The step by step explanation is shown in the attachment.

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Answer:

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