Answer:
a) m = 69.0 kg
b) release some gas in the opposite direction to the astronaut's movement
Explanation:
a) Let's use Newton's second law
F = m a
m = F / a
m = 60.0 / 0.870
m = 69.0 kg
b) when we exert a force on the astronaut it acquires a momentum po, as the astronaut system plus spacecraft is isolated, the momentum is conserved
p₀ = p_f
m v = M v '
v ’=
so we see that the ship is moving backwards, but since the mass of the ship is much greater than the mass of the astronaut, the speed of the ship is very small.
One method to avoid this effect is to release some gas in the opposite direction to the astronaut's movement so that the initial momentum of the astronaut plus the gas is zero and therefore no movement is created in the spacecraft.
Answer: 8.6 µm
Explanation:
At a long distance from the source, the components (the electric and magnetic fields) of the electromagnetic waves, behave like plane waves, so the equation for the y component of the electric field obeys an equation like this one:
Ey =Emax cos (kx-ωt)
So, we can write the following equality:
ω= 2.2 1014 rad/sec
The angular frequency and the linear frequency are related as follows:
f = ω/ 2π= 2.2 1014 / 2π (rad/sec) / rad = 0.35 1014 1/sec
In an electromagnetic wave propagating through vacuum, the speed of the wave is just the speed of light, c.
The wavelength, speed and frequency, are related by this equation:
λ = c/f
λ = 3.108 m/s / 0.35. 1014 1/s = 8.6 µm.
The amount of current passing through the point is 1 A
The amount of current passing through the point can be calculated using the formula below.
⇒ Formula:
- Q = i/t......................... Equation 1
⇒ Where:
- Q = Charge
- i = current
- t = time.
⇒ Make "i" the subject of the equation.
- i = Qt....................... Equation 2
From the question,
⇒ Given:
- Q = 1000 millicoulombs = 1 coulombs
- t = 1 seconds. (Assuming the time is 1 seconds)
⇒ Substitute these values into equation 2
Hence, The amount of current passing through the point is 1 A.
Learn more about charges here: brainly.com/question/4158552
You should write meter per second square for the acceleration in words