The ball rolled for 13.2 s
<h3>Further explanation</h3>Speed is scalar and no direction
A bowling ball rolls 33 m, with average speed = 2.5 m/s
So elapsed time :
A 50kg skater at rest on a frictionless rink throws a 2kg ball, giving the ball a velocity of 10m/s. Which statement describes t
1 answer:
You might be interested in
Answer:
The average induced emf in the loop is 0.20 V
Explanation:
Given:
Radius of loop m
Magnetic field T
Change in time sec
According to the faraday's law,
Induced emf is given by
Where magnetic flux
( here
)
Where
We neglect minus sign because it's shows lenz law
V
Therefore, the average induced emf in the loop is 0.20 V
The force applied to lift the crate is 171 N
Explanation:
The lever works on the principle of equilibrium of moments, so we can write:
where
is the force in input
is the arm of the input force
is the output force
is the arm of the output force
For the lever in this problem, we have:
(force applied)
Solving the equation for , we find the force applied to lift the crate:
Learn more about levers:
#LearnwithBrainly
Answer:
a) v = 0.7071 v₀, b) v= v₀, c) v = 0.577 v₀, d) v = 1.41 v₀, e) v = 0.447 v₀
Explanation:
The speed of a wave along an eta string given by the expression
v =
where T is the tension of the string and μ is linear density
a) the mass of the cable is double
m = 2m₀
let's find the new linear density
μ = m / l
iinitial density
μ₀ = m₀ / l
final density
μ = 2m₀ / lo
μ = 2 μ₀
we substitute in the equation for the velocity
initial v₀ =
with the new dough
v =
v = 1 /√2 \sqrt{ \frac{T_o}{ \mu_o} }
v = 1 /√2 v₀
v = 0.7071 v₀
b) we double the length of the cable
If the cable also increases its mass, the relationship is maintained
μ = μ₀
in this case the speed does not change
c) the cable l = l₀ and m = 3m₀
we look for the density
μ = 3m₀ / l₀
μ = 3 m₀/l₀
μ = 3 μ₀
v =
v = 1 /√3 v₀
v = 0.577 v₀
d) l = 2l₀
μ = m₀ / 2l₀
μ = μ₀/ 2
v =
v = √2 v₀
v = 1.41 v₀
e) m = 10m₀ and l = 2l₀
we look for the density
μ = 10 m₀/2l₀
μ = 5 μ₀
we look for speed
v =
v = 1 /√5 v₀
v = 0.447 v₀