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3 years ago

14

A 50kg skater at rest on a frictionless rink throws a 2kg ball, giving the ball a velocity of 10m/s. Which statement describes t

he skaters subsequent motion?

1 answer:

Andreas93 [3]3 years ago

3 0

0.4m/s in the opposite direction of the ball.

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EMERGENCY! PLEASE HELP!

hichkok12 [17]

Answer: Volume = 1080m^3

Explanation:

Given that the prism has a 15 m by 18 m rectangular base and a height of 4 m

Volume is the product of length, breath and height. That is

Volume = L × B × H

Where

L = 18 m

B = 15m

H = 4m

Using the formula above gives:

Volume V = 18 × 15 × 4

V = 1080 m^3

8 0

3 years ago

Where does body heat come from?

ruslelena [56]

Friction produces heat

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2 years ago

Read 2 more answers

How many signifficant figures do the following number have 258

Romashka [77]

Answer:

<u>Facts about 258</u>

<u>Sig Figs</u>

3

<u>258</u>

<u>Decimals</u>

0

<u>Scientific Notation</u>

2.58 × 102

<u>E-Notation</u>

2.58e+2

<u>Words</u>

two hundred fifty-eight

Explanation:

258 Rounded to Fewer Sig Figs

2 260 2.6 × 102

1 300 3 × 102

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2 years ago

Technician A says that when the MIL is on, the technician should retrieve the DTC and follow the manufacturer's recommended proc

evablogger [386]

Answer:

i think its both A and ab

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3 years ago

A runner taking part in the 200 m dash must run around the end of a track that has a circular arc with a radius of curvature of

34kurt

Answer:

The centripetal acceleration of the runner is $1.73\ m/s^2$ .

Explanation:

Given that,

A runner completes the 200 m dash in 24.0 s and runs at constant speed throughout the race. We need to find the centripetal acceleration as he runs the curved portion of the track. We know that the centripetal acceleration is given by :

$a=\dfrac{v^2}{r}$

v is the velocity of runner

$v=\dfrac{200\ m}{24\ s}\\\\v=8.34\ m/s$

Centripetal acceleration,

$a=\dfrac{(8.34)^2}{40}\\\\a=1.73\ m/s^2$

So, the centripetal acceleration of the runner is $1.73\ m/s^2$ . Hence, this is the required solution.

5 0

3 years ago