What three things are carried throughout the body by the cardiovascular system

A 3.10-mm-long, 430 kgkg steel beam extends horizontally from the point where it has been bolted to the framework of a new build

Alex17521 [72]

Answer:

Explanation:

Given that,

The length of the beam L = 3.10m

The mass of the steam beam $m_1$ = 430kg

The mass of worker $m_2$ = 69.0kg

The distance from the fixed point to centre of gravity of beam = $\frac{L}{2}$

and our length of beam is 3.10m

so the distance from the fixed point to centre of gravity of beam is

$\frac{3.10}{2}=1.55m$

Then the net torque is

$=-W_sL'-W_wL\\\\=-(W_sL'+W_wL)$

$W_s$ is the weight of steel rod

$=430\times9.8=4214N$

$W_w$ is the weight of the worker

$=69\times9.8\\\\=676.2N$

Torque can now be calculated

$-(4214\times1.55+676.2\times3.9)Nm\\\\-(6531.7+2637.18)Nm\\\\-(9168.88)Nm$

≅ 9169Nm

<h3>Therefore,the magnitude of the torque is 9169Nm</h3>

4 0

3 years ago

A hula hoop is rolling along the ground with a translational speed of 26 ft/s. It rolls up a hill that is 16 ft high. Determine

nikklg [1K]

Answer:12.8 ft/s

Explanation:

Given

Speed of hoop $v=26\ ft/s$

height of top $h=16\ ft$

Initial energy at bottom is

$E_b=\frac{1}{2}mv^2+\frac{1}{2}I\omega ^2$

Where m=mass of hoop

I=moment of inertia of hoop

$\omega$ =angular velocity

for pure rolling $v=\omega R$

$I=mR^2$

$E_b=\frac{1}{2}mv^2+\frac{1}{2}mR^2\times (\frac{v}{R})^2$

$E_b=mv^2=m(26)^2=676m$

Energy required to reach at top

$E_T=mgh=m\times 32.2\times 16$

$E_T=512.2m$

Thus 512.2 m is converted energy is spent to raise the potential energy of hoop and remaining is in the form of kinetic and rotational energy

$\Delta E=676m-512.2m=163.8m$

Therefore

$163.8 m=mv^2$

$v=\sqrt{163.8}$

$v=12.798\approx 12.8\ ft/s$

7 0

3 years ago

A 3.4kg aluminium ball has an apparent mass of 2.10kg when submerged in a particular liquid. Calculate the density of the liquid

Shalnov [3]

Answer:

1083.3kg/m ³

Explanation:

Given parameters:

Mass of aluminium ball = 3.4kg

Apparent mass of ball = 2.1kg

Unknown:

Density of the liquid = ?

Solution:

Density is is the mass per unit volume of any give substance;

Density = $\frac{mass}{volume}$

Now, we must understand that the apparent weight of the aluminium is the part of its weight supported by the fluid;

Pl = $\frac{Ml}{Vl}$

Pl = density of liquid

Ml = mass of liquid

Vl = volume of liquid

Mass of liquid = Mal - Mapparent

Mal = mass of aluminium

The volume of liquid displaced is the same as the volume of the aluminium according to Archimedes's principle;

Ml = Pl x Vl

Val = Vl

Val volume of aluminium

Vl = volume of liquid

****

Pal = $\frac{Mal}{Val}$

Val = $\frac{Mal}{Pal}$

Val = volume of aluminium

Mal = mass of aluminium

Pal = density of aluminium

*****

Since the Val = Vl

Ml = Pl x $\frac{Mal}{Pal}$

Since

Ml = Mal - Mapparent

Mal - Mapparent = Pl x $\frac{Mal}{Pal}$

Pal = density of aluminium = 2712 kg/m ³

3.4 - 2.1 = Pl x $\frac{3.4}{2712}$

1.3 = Pl x 0.00123

Pl = 1083.3kg/m ³

5 0

3 years ago

The Astronomer Carl Sagan is famous. Why?

Zolol [24]

Mainly because he was Johnny Carson's advisor and consultant
on space, astronomy, and science in general, and he appeared
on The Tonight Show Starring Johnny Carson many times.

6 0

3 years ago

What causes the different appearances of the moon?

VladimirAG [237]

It depends on where the sun and earth is.

4 0

3 years ago