Explanation:
As per the problem,
When q > 0 then -q is a negative charge . Since, change in potential energy () increases.
or, > 0
or,
Therefore, both positive and negative charge will move from to and as so both of them move through a negative potential difference.
Thus, we can conclude that the true statements are as follows.
- The positively charged object moves through a negative potential difference between A and B (that is, VB - VA < 0).
- The negatively charged object moves through a negative potential difference between A and B (that is, VB - VA < 0).
Answer:
Crest: the top point of a wave
Trough: the lowest point of a wave
Wavelength: the distance from one crest to the next crest OR from one trough to the next trough
Amplitude: the distance the wave travels from the initial position (that would be that line in the middle) in either direction
To calculate the temperature of the log we need the Stefan-Boltzmann's law:
P=A*ε*σ*T⁴, where P is the power emitted by the body,
A is the total surface area of the body, in our case it is a cylinder so A=r²π*h where r is the radius of the base of the cylinder and h is the height of the cylinder,
σ is the Stefan-Boltzmann constant, T is temperature and ε is emissivity .
Here we are approximating the log to be a black body.
The area of the cylinder:
A=r²*π*h, r=d/2=0.75/2=0.375 m, where d is the diameter, h=0.18 m
A=0.07948 m²
Lets solve the equation for temperature T:
T⁴=P/(σ*ε*A) and take the 4th root to get T:
T=⁴√{P/(σ*ε*A)}=⁴√{38000/((5.67*10^-8)*1*0.07948)} = ⁴√(8.432*10^12)= 1704.06 C
So the temperature of the log is T= 1704 C
Answer:
Short
Explanation:
A short circuit has basically no resistance.....kinda like just twisting the + and - wires together....sparks will fly !
Answer:
The first answer.
Explanation:
Because it uses asexual reproduction which involves two organisms creating offspring and because the older cat does not have the same exact fur coat, the father/mother would have that fur coat. meaning it was inherited from the parents.
P.S can i have brainly :)