Answer:
Where is the graph??
If a car travels from zero to 4 m/s ins 8 sec
a = 4 / 8 = .5 m/s^2
V (2) = 2 * .5 = 1 m/s after 2 sec
S = V t + 1/2 a t^2
S = 1 * 3.9 + 1/2 * 1/2 *3.9^2 = 3.9 + 3.80 = 7.70 m from 2 to 5.9 sec
Check:
Total distance traveled = 1/2 a t^2 = 5.9^2 / 4 = 8.70 m
Distance traveled in 2 sec = 1/2 * 1/2 * 4 = 1 m
Total distance from 2 to 5.9 = 8.7 - 1 = 7.7 m agreeing with thw above
140 ? i’m guessing there doesn’t look like there’s much to the question
Yessss how many you have very interesting
Answer:
Diana's speed relative to ground is <u>16 km/h</u> in the direction of motion of train.
Explanation:
Given:
Velocity of train in forward direction is, 
Here, 
Velocity of Diana relative to train in the backward direction is, 
Negative sign implies backward motion or motion opposite to the direction of train's motion. Here, Diana is walking from front of train to back. So, Diana is moving in the opposite direction.
Now, we know that, for two bodies 'A' and 'B', velocity of 'A' relative to ground is given as:
Therefore, velocity of Diana relative to ground is given as:
So, Diana's speed relative to ground is 16 km/h in the direction of motion of train.
Cathode rays are negatively charged
Explanation:
Thomson's cathode ray beam bent towards the positively charged plate. With this information, he was able to conclude that the rays were negatively charged.
Cathode rays were discovered by J.J. Thomson based on his experiment on the gas discharge tube. He was able to discover some of the properties of the wave.
One notable one was that he observed that the rays deflected towards the positively charged plate.
Since unlike poles attract then he concluded that the cathode rays were negatively charged.
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