Find the order of magnitude of your age in seconds
1 answer:
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Answer:
The force is
Explanation:
The diagram for this question is shown on the first uploaded image
At Equilibrium the summation of the of force on the vertical axis is zero
i.e
=>
is the is the speed of water at the nozzle which can be mathematically evaluated as
substituting for R and
for
is the is the speed of water at the pipe which can be mathematically evaluated as
substituting for R and
for
is he density of water with value
Substituting values into the equation above
At Equilibrium the summation of the of force on the horizontal axis is zero
i.e
=>
Since The speed at both A and B nozzle are the same then remains the same
Substituting values
=>
Hence the force acting on the flange bolts required to hold the nozzle in place is
Answer:
The shell hit at a distance of 1.9 x 10² km
The time of flight of the shell was 5.3 x 10² s
Explanation:
The position of the shell is given by the vector "r":
r = (x0 + v0 * t * cos α ; y0 + v0 * t * sin α + 1/2 g t²)
where:
x0 = initial horizontal position
v0 = magnitude of the initial velocity
t = time
α = launching angle
y0 = initial vertical position
g = acceleration of gravity
When the shell hit, the vertical component (ry) of the vector position r is 0. See figure.
Then:
ry = 0 = y0 + v0 * t * sin α + 1/2 g t²
Since the gun is at the center of our system of reference, y0 and x0 = 0
0 = t (v0 sin α + 1/2 g t)
t= 0 is discarded as solution
v0 sin α + 1/2 g t = 0
t = -2v0 sin α / g
t = (-2 * 2610 m/s * sin 81.9°)/ (-9.8 m/s²) = 5.3 x 10² s. This is the time of flight of the shell until it hit.
Then, the distance at which the shell hit is:
Distance = Module of r = ( x0 + v0 * t * cos α; 0) = x0 + v0 * t * cos α
Distance = 2.61 km/s * 5.3 x 10² s * cos 81.9 = 1.9 x 10² km
What you need to know is that the force is
F=ma
The force is the product of mass and acceleration
this means that the acceleration is
a=F/m
a) The force is halved?
this means that f will be
now:
a=
So the accelaration will also he halved (it's the original acceleratation divided by 2)
b) The object's mass is halved?
a=
=a=
which is the original acceleration times two!! so it will double
c) The force and the object's mass are both halved?
now we have
a=
=a=
=a=
so they will cancel each other out and the acceleration will stay the same!
F=ma
The force is the product of mass and acceleration
this means that the acceleration is
a=F/m
a) The force is halved?
this means that f will be
a=
So the accelaration will also he halved (it's the original acceleratation divided by 2)
b) The object's mass is halved?
a=
which is the original acceleration times two!! so it will double
c) The force and the object's mass are both halved?
now we have
a=
so they will cancel each other out and the acceleration will stay the same!