Such information is valid when A. it is not biased.
There is no bias in science - the results are either correct or incorrect; personal opinions have nothing to do with that. B is incorrect because the point of experiments is that they can be repeated to achieve the same results. C and D are likewise incorrect as primary sources are important, and you can share the results with others if you want to.
Answer:
Cp = 4756 [J/kg*°C]
Explanation:
In order to calculate the specific heat of water, we must use the equation of energy for heat or heat transfer equation.
Q = m*Cp*(T_f - T_i)/t
where:
Q = heat transfer = 2.6 [kW] = 2600[W]
m = mass of the water = 0.8 [kg]
Cp = specific heat of water [J/kg*°C]
T_f = final temperature of the water = 100 [°C]
T_i = initial temperature of the water = 18 [°C]
t = time = 120 [s]
Now clearing the Cp, we have:
Cp = Q*t/(m*(T_f - T_i))
Now replacing
Cp = (2600*120)/(0.8*(100-18))
Cp = 4756 [J/kg*°C]
Answer:
Explanation:
Given:
- file size to be transmitted,
- transmission rate of data,
- propagation speed,
- distance of data transfer,
<u>Now the delay in data transfer from source to destination for each 10 Mb:</u>
<u>Now this time is taken for each 10 Mb of data transfer and we have 30 Mb to transfer:</u>
So,
The frequency of the wave is determined as 7.96 Hz.
<h3>
Frequency of the wave</h3>
The frequency of the wave is calculated as follows;
y = A sin(ωt - kx)
where;
- A is amplitude of the wave
- ω is angular speed of the wave
ω = 2πf
f = ω/2π
f = (50)/(2π)
f = 7.96 Hz
Thus, the frequency of the wave is determined as 7.96 Hz.
Learn more about frequency of waves here: brainly.com/question/6297363
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Given:
heat generated by John's cooling system, 
= 45 W (1)
If ρ, A, and v corresponds to John's cooling system then let 
be the variables for Mike's system then:
Formula use:
Heat generated,
where,
= density
A = area
v = velocity
Solution:
for Mike's cooling system:
= 
⇒ = 
× A × 
= 4.513
A
Using eqn (1) in the above eqn, we get:
= 4.513 × 45 = 203.09 W
