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NeTakaya
2 years ago
8

Does air resistance affect the motion of a falling object differently when the mass is greater?

Physics
1 answer:
mixas84 [53]2 years ago
8 0
<span>NO.

Air resistance does not affect the motion of a falling object differently when the mass is greater because the mass of an object does not in any way affect the speed of falling due to gravity, and air resistance depends only on the speed of the object and its surface area.</span>
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Calculate the period of a spring if it has a mass of 5 kg and a spring constant of 6 N/m
otez555 [7]

Answer: The period of a spring if it has a mass of 5 kg and a spring constant of 6 N/m is 5.73 sec.

Explanation:

Given: Mass = 5 kg

Spring constant = 6 N/m

Formula used to calculate period is as follows.

T = 2 \pi \sqrt\frac{m}{k}

where,

T = period

m = mass

k = spring constant

Substitute the values into above formula as follows.

T = 2 \pi \sqrt\frac{m}{k}\\= 2 \times 3.14 \times \sqrt\frac{5}{6}\\= 5.73 s

Thus, we can conclude that the period of a spring if it has a mass of 5 kg and a spring constant of 6 N/m is 5.73 sec.

5 0
3 years ago
Why is Pluto considered less of an oddball planet now?
solmaris [256]

Answer:

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Explanation:

4 0
2 years ago
If we increase the distance traveled when doing work, and keep all other factors the same, what will happen?
stepladder [879]

Answer: D

Explanation:

A -amount of work

F-force

s-distance

If you keep same Force(F) and increase distance(s), amount of work will increase, according to:

A=F*s

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3 years ago
While filming an intense action sequence for the next James Bond movie, a controlled explosion detonates 1.3 km away from the ac
brilliants [131]

To solve this problem we must basically resort to the kinematic equations of movement. For which speed is defined as the distance traveled in a given time. Mathematically this can be expressed as

v = \frac{d}{t}

Where

d = Distance

t = time

For which clearing the time we will have the expression

t = \frac{d}{v}

Since we have two 'fluids' in which the sound travels at different speeds we will have that for the rock the time elapsed to feel the explosion will be:

t = \frac{1300m}{3000m/s}

t = 0.433s

In the case of the atmosphere -composite of air- the average speed of sound is 343m / s, therefore it will take

t = \frac{1300m}{343m/s}

t = 3.79s

The total difference between the two times would be

\Delta t = 3.79s-0.433s

\Delta t = 3.357s

Therefore 3.357s will pass between when they feel the explosion and when they hear it

8 0
3 years ago
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