Ask question

Ask question

All categories

alukav5142 [94]

3 years ago

7

True or false—If a rock is thrown into the air, the increase in the height would increase the rock’s kinetic energy, and then th

e increase in the velocity as it falls to the ground would increase its potential energy.

1 answer:

nlexa [21]3 years ago

5 0

I think that this is false but I am not sure

You might be interested in

A drop of oil of volume 10m it spread out on water to make a circular firm of radius 10m calculate the tickness of the firm

Effectus [21]

Answer:

h = 3.1 cm

Explanation:

Given that,

The volume of a oil drop, V = 10 m

Radius, r = 10 m

We need to find the thickness of the film. The film is in the form of a cylinder whose volume is as follows :

$V=\pi r^2 h\\\\h=\dfrac{V}{\pi r^2}\\\\h=\dfrac{10}{\pi \times 10^2}\\\\h=0.031\ m\\\\h=3.1\ cm$

So, the thickness of the film is equal to 3.1 cm.

8 0

3 years ago

If a tank filled with water contains a block and the height of the water above point A within the block is 0.6 meter, what's the

garri49 [273]

$Given:\\\rho=1000 \frac{kg}{m^3}\\g=9.8 \frac{m}{s^2} \\h=0.6m\\\\Find:\\p=?\\\\Solution:\\\\p=\rho gh\\\\p=1000 \frac{kg}{m^3}\cdot 9.8 \frac{m}{s^2} \cdot0.6m=5880Pa=5.88kPa\\\\Correct\;is\;answer\;\;D$

6 0

3 years ago

Read 2 more answers

How long does it take the projectile to reach its highest point in its trajectory?

NeTakaya

Answer:

It takes about 88 seconds for the cannonball to reach its maximum height (ignoring air resistance).

Explanation:

3 0

3 years ago

You stand on top a building 44 m tall with a water balloon. You drop the water balloon from rest. How fast is the balloon moving

BabaBlast [244]

Y₀ = initial position of the balloon at the top of the building = 44 m

Y = final position of the balloon at halfway down the building = 44/2 = 22 m

a = acceleration of the balloon = - 9.8 m/s²

v₀ = initial velocity of the balloon = 0 m/s

v = final velocity of the balloon = ?

using the kinematics equation

v² = v₀² + 2 a (Y - Y₀)

inserting the values

v² = 0² + 2 (- 9.8) (22 - 44)

v = 20.78 m/s

4 0

3 years ago

The temperatureTdin degrees Fahrenheit in terms of the Celsius temperaturedis given by=Td+9/5d+32.The temperatureCvin degrees Ce

Shalnov [3]

Answer:

$T_F=\frac{9}{5}(T_K-273)+32$

Explanation:

Since the temperature in degrees Fahrenheit in terms of the Celsius is given by the formula $T_F=\frac{9}{5}T_C+32$ and the temperature in degrees Celsius in terms of the Kelvin temperature is given by the formula $T_C=T_K-273$ , we can use the second formula and substitute it straight into the first formula (since a simplification is not being asked), obtaining $T_F=\frac{9}{5}(T_K-273)+32$ .

7 0

3 years ago