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alukav5142 [94]
2 years ago
7

True or false—If a rock is thrown into the air, the increase in the height would increase the rock’s kinetic energy, and then th

e increase in the velocity as it falls to the ground would increase its potential energy.
Physics
1 answer:
nlexa [21]2 years ago
5 0
I think that this is false but I am not sure
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Distance and ___ are really the same quantity. A. length b. direction c. speed d. displacement​
Oksi-84 [34.3K]

Answer:

distance and length are the same quantity

4 0
3 years ago
Order the seven basic spectral types from hottest to coldest.
vfiekz [6]

Answer:

There are basically seven spectral types which are used for classifying the stars and it is arranged in the order of increasing temperature from the hottest temperature to the coldest division are: O, B, A, F, G, K, and M. These categories are basically divided into the sub category in the spectral where O is the hottest type and M is the coldest type.  

8 0
3 years ago
A woman exerts a horizontal force of 4 pounds on a box as she pushes it up a ramp that is 10 feet long and inclined at an angle
stealth61 [152]

Answer:

W = 34.64 ft-lbs

Explanation:

given,

Horizontal force = 4 lb

distance of push, d = 10 ft

angle of ramp, θ = 30°

Work done on the box = ?

We know,

W = F.d cos θ

W = 4 x 10 x cos 30°

W = 40 x 0.8660

W = 34.64 ft-lbs

Hence, work done on the box is equal to W = 34.64 ft-lbs

6 0
3 years ago
Does the mass of a parachute affect terminal velocity?
vovangra [49]

Answer:

The greater weight increases the terminal velocity by acting as an extra force against gravity and air resistance.

6 0
2 years ago
A car whose total mass is 800kg travelling with a uniform velocity of 20m/s suddenly observes a stationary dog 50m ahead on its
maxonik [38]

Answer:

The driver hits the stationery dog because the applied force is less than required force

Explanation:

Kinetic energy will be given by

KE=0.5mv^{2} where m is the mass of the vehicle and v is the speed/velocity of the vehicle.

Substituting 800 Kg for m and 20 m/s for v we obtain

KE=0.5*800*(20 m/s)^{2}=160,000

Frictional force by vehicle pads is given by

Fr=\frac {KE}{d} where d is the distance moved

Substituting 160000 for KE and 50 m for d we obtain

Fr=\frac {160000}{50}=3200 N

Therefore, the vehicle hits the dog since the required force is 3200N but the driver applied only 2000 N

7 0
2 years ago
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