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UNO [17]
3 years ago
10

State the pressure law?

Physics
1 answer:
yarga [219]3 years ago
4 0
The pressure law states: "For a fixed mass of gas, at a constant volume, thepressure<span> (p) is directly proportional to the absolute temperature (T)."</span>
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Two students are standing on a fire escape, one twice as high as the other. Simultaneously, each drops a ball.
almond37 [142]
The second ball should strike at double the original t value
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What color is reflected off of most plant leaves?
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Green is reflected off of most plant leaves.
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What is a unit of acceleration?<br> a. m/s<br> b. m/s2<br> c. m2/s<br> d. kg-m/s2
Basile [38]
A). m/s ... meters per second. 
                 That's a speed.

b). m/s² ... (meters per second) per second. 
                   Acceleration
.

c). m²/s ... square meters per second.
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                 Meaningless unit, unless you happen to be
                     a painter of houses or a mower of lawns.

d). kg-m/s² ... (mass) x (an acceleration). 
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                       In fact, it's the definition of "newton".
3 0
3 years ago
A solid sphere has a radius of 0.200 m and a mass of 150.0 kg. how much work is required to get the sphere rolling with an angul
Allisa [31]

Here in this case we can use work energy theorem

As per work energy theorem

Work done by all forces = Change in kinetic Energy of the object

Total kinetic energy of the solid sphere is ZERO initially as it is given at rest.

Final total kinetic energy is sum of rotational kinetic energy and translational kinetic energy

KE = \frac{1}{2}Iw^2 +\frac{1}{2} mv^2

also we know that

I = \frac{2}{5}mR^2

w= \frac{v}{R}

Now kinetic energy is given by

KE = \frac{1}{2}(\frac{2}{5}mR^2)w^2 +\frac{1}{2} m(Rw)^2

KE = \frac{1}{5}mR^2w^2 +\frac{1}{2} mR^2w^2

KE = \frac{7}{10}mR^2w^2

KE = \frac{7}{10}*150*(0.200)^2(50)^2

KE = 10500 J

Now by work energy theorem

Work done = 10500 - 0 = 10500 J

So in the above case work done on sphere is 10500 J

7 0
2 years ago
19. A mass of gas has a volume of 4 m3, a temperature of 290 K, and an absolute pressure of 475 kPa. When the gas is allowed to
Aleks [24]

Recall this gas law:

\frac{P₁V₁}{T₁} = \frac{P₂V}{T₂}

P₁ and P₂ are the initial and final pressures.

V₁ and V₂ are the initial and final volumes.

T₁ and T₂ are the initial and final temperatures.

Given values:

P₁ = 475kPa

V₁ = 4m³, V₂ = 6.5m³

T₁ = 290K, T₂ = 277K

Substitute the terms in the equation with the given values and solve for Pf:

\frac{475*4}{290} = \frac{P₂*6.5}{277}

<h3>P₂ = 279.2kPa</h3>
8 0
3 years ago
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