For this problem, we use the Coulomb's law written in equation as:
F = kQ₁Q₂/d²
where
F is the electrical force
k is a constant equal to 9×10⁹
Q₁ and Q₂ are the charge of the two objects
d is the distance between the two objects
Substituting the values:
F = (9×10⁹)(-22×10⁻⁹ C)(-22×10⁻⁹ C)/(0.10 m)²
F = 0.0004356 N
Answer:
The voltage will be 0.0125V
Explanation:
See the picture attached
B. The voltage is the same across all resistors in the circuit.
<em>number of waves that pass a given point in one second is called <u>frequency..</u></em>
