If an object is dropped from a tall building and hits the ground 3.0 s later, what is the velocity of the object when it hits th
1 answer:
You might be interested in
Answer:
E = 5291.00 N/C
Explanation:
Expression for capacitance is
where
A is area of square plate
D = DISTANCE BETWEEN THE PLATE
We know that capacitrnce and charge is related as
v = 9.523 V
Electric field is given as
=
E = 5291.00 V/m
E = 5291.00 N/C
Answer:
You could use newton’s second law to calculate the force applied to an object if you knew the objects mass and its <u>acceleration.</u>
Explanation:
By, Newtons second law, the force applied on an object directly varies with the acceleration caused and the mass of the object.
This is given by :
Where represents force applied on the object ,
represents mass of the object and
represents the acceleration.
In order to calculate force applied on object we require the mass of the object and its acceleration. The force can be calculated by finding the product of mass and acceleration of the object.