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lys-0071 [83]
3 years ago
11

A fish swims 12.0 m in 5.0 s. It swims the first 4.0 m in 2.0 s, the next 3.0 m in 1.2 s, and the last 5.0 m in 1.8 s. What is t

he average velocity of the fish during the time interval between 0.0 s and 3.2 s?
Physics
2 answers:
xz_007 [3.2K]3 years ago
7 0
Use the distance swan and the time elapsed in that interval.

Average velocity = distance / time

Average velocity = [4.0 m + 3.0m] / 3.2 s = 2.1875 m/s 
frosja888 [35]3 years ago
6 0

Answer:

IT IS OPTION D

Explanation:

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3 years ago
Which of the following statements is true about magnetic fields produced by current-carrying wires?
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3 years ago
Read 2 more answers
in a tall building, a certain window is 500 meters above the ground.A tennis ball is catapulted horizontally out of the window w
expeople1 [14]

The tennis ball lands at a point 40.4 m from the base of the building.

The tennis ball is projected with a horizontal velocity <em>u</em> from a window, which is at a height <em>y</em> from the ground. The ball lands at a distance <em>x</em> from the base of the building. Let the ball take a time <em>t</em> to reach the ground. In the time <em>t</em> ,the ball falls a vertical distance <em>y</em> and also travel a horizontal distance <em>x</em>.

The initial vertical velocity of the ball is zero, since the ball is projected in the horizontal direction.  The ball falls down under the action of gravitational force.

Thus, use the equation of motion,

y=\frac{1}{2} gt^2

rewrite the expression for <em>t</em> and calculate the value of <em>t</em> using 9.81 m/s²for <em>g</em> and 500 m for <em>y</em>.

t=\sqrt{\frac{2y}{g} } \\ =\sqrt\frac{(2)(500m)}{9.81m/s^2}  \\ =10.096 s

The horizontal distance <em>x</em> is traveled using the constant velocity <em>u </em>since no force acts on the ball in the horizontal direction.

Therefore,

x=ut

Substitute 4 m/s for <em>u</em> and 10.096 s for <em>t</em>

x=ut\\ =(4m/s)(10.096s)\\ =40.384m=40.4 m

Thus, the ball lands at a point 40.4 m from the base of the building.



6 0
3 years ago
Can someone help me this question ​
vladimir2022 [97]

Answer:

Volume of wood is 68-50 = 18 cm³

Explanation:

<h2>Hope it helps you</h2>
4 0
3 years ago
If homeboy joe is pushing a box with force of 57.0 in the horizontal direction and -15.0 in the vertical direction. What is the
Ksenya-84 [330]

Answer:

The magnitude of joes net force is 58.9.

Explanation:

The magnitude of the net force is given by:

F_{net} = \sqrt{F_{x}^{2} + F_{y}^{2}}

Where:

F_{x}: is the force in the horizontal direction = 57.0

F_{y}: is the force in the vertical direction = -15.0

F_{net} = \sqrt{(57.0)^{2} + (-15.0)^{2}} = 58.9

Therefore, the magnitude of joes net force is 58.9.

I hope it helps you!                                                                                        

5 0
2 years ago
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