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lys-0071 [83]
3 years ago
11

A fish swims 12.0 m in 5.0 s. It swims the first 4.0 m in 2.0 s, the next 3.0 m in 1.2 s, and the last 5.0 m in 1.8 s. What is t

he average velocity of the fish during the time interval between 0.0 s and 3.2 s?
Physics
2 answers:
xz_007 [3.2K]3 years ago
7 0
Use the distance swan and the time elapsed in that interval.

Average velocity = distance / time

Average velocity = [4.0 m + 3.0m] / 3.2 s = 2.1875 m/s 
frosja888 [35]3 years ago
6 0

Answer:

IT IS OPTION D

Explanation:

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A stone of mass 0.2 kg falls with an acceleration of 10.0 m/s. How big is the force that causes this acceleration?
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Answer:

\boxed {\boxed {\sf 2 \ Newtons}}

Explanation:

According to Newton's Second Law of Motion, force is the product of mass and acceleration.

F= m \times a

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Substitute the values into the formula.

F= 0.2 \ kg * 10.0 \ m/s^2

Multiply.

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Convert the units.

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F= 2 \ N

The force is <u>2 Newtons.</u>

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