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lys-0071 [83]
3 years ago
11

A fish swims 12.0 m in 5.0 s. It swims the first 4.0 m in 2.0 s, the next 3.0 m in 1.2 s, and the last 5.0 m in 1.8 s. What is t

he average velocity of the fish during the time interval between 0.0 s and 3.2 s?
Physics
2 answers:
xz_007 [3.2K]3 years ago
7 0
Use the distance swan and the time elapsed in that interval.

Average velocity = distance / time

Average velocity = [4.0 m + 3.0m] / 3.2 s = 2.1875 m/s 
frosja888 [35]3 years ago
6 0

Answer:

IT IS OPTION D

Explanation:

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A wave travels a distance of 60cm in 3s. The distance blw successive crests of thd wave is 4cm. What is the frequency?
schepotkina [342]
Data:
ΔS = 60cm
Δt = 3s
Vm = ?

Vm = ΔS/Δt 
Vm =  \frac{60}{3}
Vm = 20cm/s

We have:

Vm = v
ΔS = λ
Δt = T

v =  \frac{\lambda}{T}
20 = \frac{\lambda}{4}
\lambda = 20*4
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Soon:

v = \lambda*f
20 = 80*f
80f = 20
f =  \frac{20}{80} simplify( \frac{\div20}{\div20} )= \frac{1}{4}
\boxed{f = 0,25Hz}


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A bag of cement weighing 325 N hangs in equilibrium from three wires. Two of the wires make angles of theta1=60.0 degrees and th
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The free body diagram of the weight with the string 3, drives to the tension T3 = weihgt => T3 = 325 N

The other free body diagram is around the joint of the three strings.

In this case, you can do the horizontal forces equilibrium equation as:

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