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Rus_ich [418]
3 years ago
15

William has a 26 -liter glass tank. First, he wants to put some marbles in it, all of the same volume. Then, he wants to fill th

e tank with water until it's completely full. If he uses 85 marbles, he will have to add 20.9 liters of water. What is the volume of each marble?
Mathematics
1 answer:
Ann [662]3 years ago
4 0

Answer: 0.06 litre or 60 ml


Step-by-step explanation:

Given: The capacity of glass tank= 26 liter

If he add 20.9 liters of water after 85 marbles to fill it completely, then

The volume of 85 marbles= 26-20.9=5.1\ liters

Since, the marbles have same volume.

∴ Volume of each marble= \frac{\text{volume of 85 marbles}}{\text{85}}

⇒ Volume of each marble=\frac{5.1\ litre}{85}=0.06\ liters

In milliliters, Volume of each marble=0.06\times1000=60ml

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D. 12

Step-by-step explanation:

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AB/AD = CB/CD

Substitute

AB/8 = 6/4

Cross multiply

AB*4 = 6*8

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Step-by-step explanation:

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A ski gondola carries skiers to the top of a mountain. assume that weights of skiers are normally distributed with a mean of 199
Allushta [10]
A) maximum mean weight of passengers = <span>load limit ÷ number of passengers
</span><span>
maximum mean weight of passengers = 3750 </span>÷ 25 = <span>150lb

</span>B)  First, find the z-score:
z = (value - mean) / stdev
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   = -1.20

We need to find P(z > -1.20) = 1 - P(z < -1.20)

Now, look at a standard normal table to find <span>P(z < -1.20) = 0.11507, therefore:
</span>P(z > -1.20) = 1 - <span>0.11507 = 0.8849

Hence, <span>the probability that the mean weight of 25 randomly selected skiers exceeds 150lb is about 88.5%</span> </span>

C) With only 20 passengers, the new maximum mean weight of passengers = 3750 ÷ 20 = <span>187.5lb

Let's repeat the steps of point B)

z = (187.5 - 199) / 41
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P(z > -0.29) = 1 - P(z < -0.29) = 1 - 0.3859 = 0.6141

</span>Hence, <span>the probability that the mean weight of 20 randomly selected skiers exceeds 187.5lb is about 61.4%

D) The mean weight of skiers is 199lb, therefore:
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The new capacity of 20 skiers is safer than 25 skiers, but we cannot consider it safe enough, since the maximum capacity should be of 18 skiers.</span>
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