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photoshop1234 [79]
3 years ago
13

Josh decided to mix some vinegar with baking soda. He knew that a reaction occurred because he made careful observations. He not

ed that the mixture started to foam up and bubble and was white in color. How did josh know that a chemical reaction occured? He was sure a reaction occured because of
Chemistry
1 answer:
velikii [3]3 years ago
6 0

Josh was sure that the reaction occurred because of the formation of carbon dioxide (CO₂) which is a gas.

Explanation:

Vinegar contains acetic acid (CH₃-COOH) and baking soda is sodium hydrogen carbonate (NaHCO₃). The reaction between these two compounds will produce sodium acetate (CH₃-COONa), carbon dioxide (CO₂) and water (H₂O).

CH₃-COOH + NaHCO₃ → CH₃-COONa + CO₂ + H₂O

Josh was sure that the reaction occurred because of the formation of carbon dioxide (CO₂) which is a gas.

Learn more about:

carbon dioxide

brainly.com/question/2840704

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If the molar absorptivity constant for the red dye solution is 5.56×104 M-1cm-1, calculate the molarity of the red dye solution
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Explanation:

a) Using Beer-Lambert's law :

Formula used :

A=\epsilon \times c\times l

where,

A = absorbance of solution = 0.945

c = concentration of solution = ?

l = length of the cell = 1.20 cm

\epsilon = molar absorptivity of this solution =5.56\times 10^4 M^{-1} cm^{-1}

0.945=5.56\times 10^4 M^{-1} cm^{-1}\times 1.20 \times c

c=1.4163\times 10^{-5} M=14.16 \mu M

(1\mu M=10^{-6} M)

14.16 μM is the molarity of the red dye solution at the optimal wavelength 519nm and absorbance value 0.945.

b) c=1.4163\times 10^{-5} mol/L

1 L of solution contains 1.4163\times 10^{-5} moles of red dye.

Mass of 1.4163\times 10^{-5} moles of red dye:

1.4163\times 10^{-5}\times 879.86g/mol=0.01246 g

(w/v)\%=\frac{\text{Mass of solute (g)}}{\text{Volume of solvent (mL)}}\times 100

red(w/v)\%=\frac{0.01246 g}{1000 mL}\times 100=0.001246\%

c) In order to dilute red dye solution by 5 times, we will need to add 1 L of water to solution of given concentration.

Concentration of red dye solution = c=1.4163\times 10^{-5} M

Concentration of red solution after dilution = c'

c=c'\times 5

1.4163\times 10^{-5} M=c'\times 5

c'=2.83\times 10^{-6} M

The final concentration of the diluted solution is 2.83\times 10^{-6} M

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