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Pachacha [2.7K]
2 years ago
11

i have a crossword thing that i got from school and one of the clues is: If there are two equal and opposite forces on something

, we say the forces are______ .Its 8 letters and the 4th letter is A. What do you think it is im so confused?
Chemistry
2 answers:
Nezavi [6.7K]2 years ago
8 0
Well the forces are balanced. Perhaps the 8th letter is not actually "A" but a "D"? 
cluponka [151]2 years ago
6 0
I would assume the answer is called attractive
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Answer:

Some are large, some are small, some have more gravity then others. Some cant handle human life. Some are very cold some are very hot.

Explanation:

7 0
2 years ago
How many grams of ammonium chloride (NH4Cl) would be required to make a saturated solution in 1000 grams of water at 50 degrees
Pavel [41]
<span>Since,
1000 grams of water = 1000 mL of water</span><span>
So, 
At any of the given temperature:
</span>1000 mL = 10 x 100 mL
<span>
moles of NH4Cl = 53.5/53.49
                          = 1.0 m
                          = 1.0 mol/Kg
Delta T = 2 x 1.86 x 1.0
             = 3.72 c
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3 0
2 years ago
A gas at 300 k and 4.0 atm is moved to a new loacation with a temperature of 250 k. The volume changes from 5.5 L to 2.0 L. What
alexgriva [62]
Answer is: <span>the pressure of the gas is 9,2 atm.
</span>p₁ = 4,0 atm.
T₁ = 300 K.
V₁ = 5,5 L.
p₂ = ?
T₂ = 250 K.
V₂ = 2,0 L.
Use combined gas law - the volume of amount of gas is proportional to the ratio of its Kelvin temperature and its pressure.<span> 
</span>p₁V₁/T₁ = p₂V₂/T₂.
4 atm · 5,5 L ÷ 300 K  = p₂ · 2,0 L ÷ 250 K.
0,0733 = 0,008p₂.
p₂ = 9,2 atm.

4 0
3 years ago
What is the molarity of solution obtained when 5.71 g of sodium carbonate-10-water is dissolved in water and made up to 250.0 cm
disa [49]

We have to know the molarity of solution obtained when 5.71 g of Na₂CO₃.10 H₂O is dissolved in water and made up to 250 cm³ solution.

The molarity of solution obtained when 5.71 g of sodium carbonate-10-water (Na₂CO₃.10 H₂O)  is dissolved in water and made up to 250.0 cm^3 solutionis: (A) 0.08 mol dm⁻³

The molarit y of solution means the number of moles of solute present in one litre of solution. Here solute is Na₂CO₃.10 H₂O and solvent is water. Volume of solution is 250 cm³.

Molar mass of Na₂CO₃.10 H₂O is 286 grams which means mass of one mole of Na₂CO₃.10 H₂O is 286 grams.

5.71 grams of Na₂CO₃.10 H₂O is equal to \frac{5.71}{286}= 0.0199 moles of Na₂CO₃.10 H₂O. So, 0.0199 moles of Na₂CO₃.10 H₂O present in 250 cm³ volume of solution.

Hence, number of moles of Na₂CO₃.10 H₂O present in one litre (equal to 1000 cm³) of solution is \frac{0.0199 X 1000}{250} = 0.0796 moles. So, the molarity of the solution is 0.0796 mol/dm³ ≅ 0.08 mol/dm³


3 0
3 years ago
Which measure is equivalent to work/distance
Bad White [126]
The amount of force is what this is for
8 0
3 years ago
Read 2 more answers
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