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LenKa [72]
3 years ago
12

when Mn2 ions are separated from the mixture, they go through a series of oxidizing and reducing steps. Write the reaction equat

ions that describe this process
Chemistry
1 answer:
goldfiish [28.3K]3 years ago
8 0

Answer: hello some part of your question is missing below is the missing part

when H₂O and H₂O₂ is added to Mn(OH)₂(s) and put in water bath to dissolve

answer : attached below

Explanation:

When Mn²⁺ ions are separated from the mixture, attached below are the requires reaction equations that shows the process of separation.

Mn²⁺ ions are separated to the right of the reaction  equations

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Atoms like sodium and lithium often lose electrons, which makes them
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What is the daughter nuclide when 0-15 experiences positron emission?
Helen [10]

The daughter isotope (a decay product)of O-15 = N-15(Nitrogen 15)

<h3>Further explanation </h3>

Radioactivity is the process of unstable isotopes to stable isotopes by decay, by emitting certain particles,  

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O-15 emits positron particles ₁e⁰, so the atomic number decreases by 1, the mass number is the same

Reaction

 \tt _8^{15}O\Rightarrow _7^{15}N+_1^0e

The mass number of the daughter isotope = 15, atomic number = 7

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5 0
3 years ago
Zinc oxide adopts a face-centered cubic arrangement. Both Zinc ions and oxide ions adopt the face-centered cubic arrangement; wi
vichka [17]

Answer:

5.41 ×10⁻²²

Explanation:

We were told right from the question that both the Zinc ions and the Zinc oxide adopts a face-centered cubic arrangement.

Then, the number of ZnO molecule in one unit cell = 4

The standard molar mass of ZnO = 81.38g

Avogadro's constant = 6.023 × 10²³ mole

∴

The mass of one unit cell of zinc oxide can be calculated as:

= \frac{4*81.38}{6.023*10^{23}}

= 5.40461564×10⁻²²

≅ 5.41 ×10⁻²²

∴ The mass of one unit cell of zinc oxide = 5.41 ×10⁻²²

3 0
2 years ago
A student weighed an empty graduated cylinder. It weighed 35.86 g. She then carefully added water to the graduated cylinder unti
Firdavs [7]

Question:

A student weighed an empty graduated cylinder. It weighed 35.86 g. She then carefully added water to the graduated cylinder until it reached the 7.5 mL mark. When she weighed the graduated cylinder again, this time with the 7.5 mL of water in it, it weighed 43.18 g. What was this student's experimental density of water?

Answer:

0.976 g/mL

Explanation:

Weight of empty cylinder = 35.86g

Volume of water = 7.5mL

Weight of cylinder + water = 43.18g

Experimental density = ?

Density of water = Mass of water / volume of water

Mass of water = (Weight of cylinder + water) - Weight of empty cylinder

Mass of water = 43.18 - 35.86 = 7.32g

Density = 7.32 / 7.5 = 0.976 g/mL

5 0
2 years ago
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