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shusha [124]
3 years ago
12

What kind of fossil is made when a creature is buried under sediment and as that sediment forms into rock the hard materials lik

e bones of the organism are formed into the rock?
Chemistry
1 answer:
Lorico [155]3 years ago
4 0

Answer:

Mold fossil

Explanation:

It's called a mold fossil because they are formed when sediments bury an organism and then the sediments are changed into rock; then the organism decays thereby leaving a cavity in the shape of the organism

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Plz help :(
ziro4ka [17]
<h2>Answer:0.5 moles,1 mole</h2>

Explanation:

Sr(NO_{3})_{2} is readily soluble in water.

Sr(NO_{3})_{2} dissolves in water to give Sr^{2+} ions and NO_{3}^{-} ions.

The reaction is

Sr(NO_{3})_{2}→Sr^{2+}+2NO_{3}^{-}

So,1 mole of Sr(NO_{3})_{2} gives 1 mole of Sr^{2+} and 2 moles of NO_{3}^{-}.

So,0.5 moles of Sr(NO_{3})_{2} gives 0.5 moles of Sr^{2+} and 1 mole of NO_{3}^{-}.

5 0
3 years ago
How many particles are in on mole?
shusha [124]

The answer is 1023 particles

6 0
3 years ago
How does a ketone react with PCl5?,
Reptile [31]

When ketone is reacted with phosphorous pentachloride, chlorination takes place at the carbonyl carbon with substitution of the oxygen atom to give a geminal dichloride (with 2 Cl atoms on same carbon) according to the following equation: 

so we can say that acetone is converted into 2,2-dichloropropane by action of PCl₅

<span />

7 0
3 years ago
Molecules in 2 moles of carbon dioxide<br>​
Maksim231197 [3]

Answer:

HAVE A NICE DAY OK

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5 0
3 years ago
Calculate the standard enthalpy change for the reaction at 25 ∘ 25 ∘ C. Standard enthalpy of formation values can be found in th
WINSTONCH [101]

<u>Answer:</u> The standard enthalpy change of the reaction is coming out to be -16.3 kJ

<u>Explanation:</u>

Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles. It is represented as \Delta H

The equation used to calculate enthalpy change is of a reaction is:  

\Delta H_{rxn}=\sum [n\times \Delta H_f(product)]-\sum [n\times \Delta H_f(reactant)]

For the given chemical reaction:

Mg(OH)_2(s)+2HCl(g)\rightarrow MgCl_2(s)+2H_2O(g)

The equation for the enthalpy change of the above reaction is:

\Delta H_{rxn}=[(1\times \Delta H_f_{(MgCl_2(s))})+(2\times \Delta H_f_{(H_2O(g))})]-[(1\times \Delta H_f_{(Mg(OH)_2(s))})+(2\times \Delta H_f_{(HCl(g))})]

We are given:

\Delta H_f_{(Mg(OH)_2(s))}=-924.5kJ/mol\\\Delta H_f_{(HCl(g))}=-92.30kJ/mol\\\Delta H_f_{(MgCl_2(s))}=-641.8kJ/mol\\\Delta H_f_{(H_2O(g))}=-241.8kJ/mol

Putting values in above equation, we get:

\Delta H_{rxn}=[(1\times (-641.8))+(2\times (-241.8))]-[(1\times (-924.5))+(2\times (-92.30))]\\\\\Delta H_{rxn}=-16.3kJ

Hence, the standard enthalpy change of the reaction is coming out to be -16.3 kJ

6 0
3 years ago
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