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How many atoms of HCl are needed to produce 0.62 moles of hydrogen gas

navik [9.2K]

Answer:

0.2 moles

Explanation:

7 0

3 years ago

Read 2 more answers

How do anion formation and valence electrons relate?

sveta [45]

Answer 1: Atoms gain valence electrons to form anions.

Explanation:

Anions are negatively charged species of an ions. Anions are formed when atoms with nearly complete octet gains electrons.

Answer 2: Emission spectrum

Explanation:

When ever electron jumps from higher energy to lower energy level energy is emitted out in the form of light.The wavelength of the light is given as $\lambda$ :

$\lambda=\frac{hc}{E}$ , E = energy, c= speed the light, h= planck constant

Answer 3: Two atoms of silicons could combine by fusion in order to create nickel.

Explanation:

Silicon has atomic number of 14 with atomic mass of 28 u.

nickel has atomic number of 28 with atomic mass of 59 u.

Two different isotopes of silicon atom will fuse together to give nickel.

$^{29}Si_{14}+^{30}Si_{14}\rightarrow^{59}Ni_{28}$

5 0

3 years ago

3. The formula for table salt is NaCl. Is table salt ionic or covalent? Explain

d1i1m1o1n [39]

Answer:

it's an ionic compound

7 0

3 years ago

When 5.00 g of NH4NO3 is dissolved in 100.0 g of water in a styrofoam cup, the T = - 3.82 ^°C. Is the process of dissolving ammo

miv72 [106K]

Answer:

The process is endothermic.

Heat is 26,9 kJ/mol

Explanation:

The dissolution of NH₄NO₃ in water is:

NH₄NO₃ → NH₄⁺ + NO₃⁻

As the change of temperature in the cup is ΔT = -3,82°C

The process is endothermic. Because the temperature is decreasing in the process. That means the process needs heat.

Assuming the heat capacity of the solution is 4.18 J/Kg :

q = -C×m×ΔT

Where q is heat, C is heat capacity (4,18J/Kg), m is mass (105g) and ΔT is change in temperature (-3,82°C)

q = 1677 J ≈ 1,68kJ

The moles of NH₄NO₃ dissolved are:

5,00g × (1mol / 80,043g) = 0,0625 moles

That means heat of this process in kJ/ mol is:

1,68kJ / 0,0625moles = 26,9 kJ/mol

I hope it helps!

8 0

3 years ago

An ideal gas in a cylindrical container of radius r and height h is kept at constant pressure p. The bottom of the container is

Juli2301 [7.4K]

Answer:

$m =\frac{p*(pi)*r^{2}*h*mw}{R*\frac{T_{1} + T_{O}}{2}}$

Explanation:

The gas ideal law is

PV= nRT (equation 1)

Where:

P = pressure

R = gas constant

T = temperature

n= moles of substance

V = volume

Working with equation 1 we can get

$n =\frac{PV}{RT}$

The number of moles is mass (m) / molecular weight (mw). Replacing this value in the equation we get.

$\frac{m}{mw} =\frac{PV}{RT}$ or

$m =\frac{P*V*mw}{R*T}$ (equation 2)

The cylindrical container has a constant pressure p

The volume is the volume of a cylinder this is

$V =(pi)*r^{2}*h$

Where:

r = radius

h = height

(pi) = number pi (3.1415)

This cylinder has a radius, r and height, h so the volume is $V =(pi)*r^{2}*h$

Since the temperatures has linear distribution, we can say that the temperature in the cylinder is the average between the temperature in the top and in the bottom of the cylinder. This is:

$T =\frac{T_{1} + T_{O}}{2}$

Replacing these values in the equation 2 we get:

$m =\frac{P*V*mw}{R*T}$ (equation 2)

$m =\frac{p*(pi)*r^{2}*h*mw}{R*\frac{T_{1} + T_{O}}{2}}$

8 0

4 years ago